Solve for c. (5)/(4)=-4c+(1)/(4)

Move term with c: Isolate the term containing c on one side of the equation. We start by moving the term without c from the right side to the left side of the equation by adding (1/4) to both sides. (5/4) + (-1/4) = -4c + (1/4) + (-1/4)Simplify both sides: Simplify both sides of the equation. On the left side, we combine like terms (5/4) and (-1/4). (5/4) - (1/4) = -4c (4/4) = -4c 1 = -4cSolve for c: Solve for c. To find c, we divide both sides of the equation by -4. 1 / (-4) = -4c / (-4) -1/4 = c

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Solve for $c$ . $\newline$ $\frac{5}{4}=-4 c+\frac{1}{4}$

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Algebra 1

Solve linear equations: mixed review

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Q. Solve for

c

\newline

\frac{5}{4}=-4 c+\frac{1}{4}

Move term with $c$ : Isolate the term containing $c$ on one side of the equation. $\newline$ We start by moving the term without $c$ from the right side to the left side of the equation by adding $(1/4)$ to both sides. $\newline$ $(5/4) + (-1/4) = -4c + (1/4) + (-1/4)$
Simplify both sides: Simplify both sides of the equation. $\newline$ On the left side, we combine like terms $(\frac{5}{4})$ and $(-\frac{1}{4})$ . $\newline$ $(\frac{5}{4}) - (\frac{1}{4}) = -4c$ $\newline$ $(\frac{4}{4}) = -4c$ $\newline$ $1 = -4c$
Solve for c: Solve for c. $\newline$ To find c, we divide both sides of the equation by -4＂).$\newline\$\frac{1}{(-4)} = \frac{-4c}{(-4)}$$\newline$$-\frac{1}{4} = c$