Solve for a. -11=(1)/(3)a-25 Answer: a=

Move Constant Term: First, we want to isolate the term containing a on one side of the equation. To do this, we can add 25 to both sides of the equation to move the constant term to the left side. -11 + 25 = (1/3)a - 25 + 25Perform Addition: Now, let's perform the addition on both sides of the equation. 14 = (1/3)aMultiply by 3: Next, we need to solve for a. To do this, we can multiply both sides of the equation by 3 to get rid of the fraction. 3 * 14 = (1/3)a * 3Find Value of a: Let's perform the multiplication to find the value of a. 42 = a

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Solve for
a.

-11=(1)/(3)a-25
Answer:
a=

Solve for $a$ . $\newline$ $-11=\frac{1}{3} a-25$ $\newline$ Answer: $a=$

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Algebra 1

Solve linear equations: mixed review

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Q. Solve for

a

\newline

-11=\frac{1}{3} a-25

\newline

Answer:

a=

Move Constant Term: First, we want to isolate the term containing $a$ on one side of the equation. To do this, we can add $25$ to both sides of the equation to move the constant term to the left side. $\newline$ $-11 + 25 = \left(\frac{1}{3}\right)a - 25 + 25$
Perform Addition: Now, let's perform the addition on both sides of the equation. $14 = \left(\frac{1}{3}\right)a$
Multiply by $3$ : Next, we need to solve for $a$ . To do this, we can multiply both sides of the equation by $3$ to get rid of the fraction. $\newline$ $3 \times 14 = \left(\frac{1}{3}\right)a \times 3$
Find Value of a: Let's perform the multiplication to find the value of $a$ . $42 = a$