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Solve for z. -15+(3)/(10)z=-12 Answer: z=

Solve for z z .\newline−15+310z=−12 -15+\frac{3}{10} z=-12 \newlineAnswer: z= z=

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Full solution

Q. Solve for z z .\newline−15+310z=−12 -15+\frac{3}{10} z=-12 \newlineAnswer: z= z=
  1. Add 1515 to isolate z: Add 1515 to both sides of the equation to isolate the term containing z.\newline−15+(310)z+15=−12+15-15 + \left(\frac{3}{10}\right)z + 15 = -12 + 15
  2. Simplify both sides: Simplify both sides of the equation. (310)z=3(\frac{3}{10})z = 3
  3. Multiply by reciprocal: Multiply both sides of the equation by the reciprocal of (310)(\frac{3}{10}) to solve for zz.103×310z=3×103\frac{10}{3} \times \frac{3}{10}z = 3 \times \frac{10}{3}
  4. Simplify to find zz: Simplify both sides of the equation.z=10z = 10

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