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y=x-2

y=3x+4
Is 
(4,2) a solution of the system?
Choose 1 answer:
(A) Yes
(B) 
No

y=x2 y=x-2 \newliney=3x+4 y=3 x+4 \newlineIs (4,2) (4,2) a solution of the system?\newlineChoose 11 answer:\newline(A) Yes\newline(B) No

Full solution

Q. y=x2 y=x-2 \newliney=3x+4 y=3 x+4 \newlineIs (4,2) (4,2) a solution of the system?\newlineChoose 11 answer:\newline(A) Yes\newline(B) No
  1. Substitute and Check First Equation: First, we will substitute the point (4,2)(4,2) into the first equation and check if it holds true. The first equation is y=x2y = x - 2. If we substitute x=4x=4 and y=2y=2, we get 2=422 = 4 - 2.
  2. Verify First Equation: After performing the calculation, we find that 2=22 = 2, which is true. Therefore, the point (4,2)(4,2) satisfies the first equation.
  3. Substitute and Check Second Equation: Next, we will substitute the point (4,2)(4,2) into the second equation and check if it holds true. The second equation is y=3x+4y = 3x + 4. If we substitute x=4x=4 and y=2y=2, we get 2=3×4+42 = 3 \times 4 + 4.
  4. Verify Second Equation: After performing the calculation, we find that 2=1(2)+42 = 1(2) + 4, which simplifies to 2=162 = 16. This is not true. Therefore, the point (4,2)(4,2) does not satisfy the second equation.
  5. Solution Evaluation: Since the point (4,2)(4,2) does not satisfy both equations, it is not a solution to the system of equations.

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