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Solve. \newlinex=2 x = -2 \newline2x+2y=8 -2x + 2y = -8 \newline(____,____)(\_\_\_\_, \_\_\_\_)

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Q. Solve. \newlinex=2 x = -2 \newline2x+2y=8 -2x + 2y = -8 \newline(____,____)(\_\_\_\_, \_\_\_\_)
  1. Substitute x=2x = -2: First, we substitute x=2x = -2 into the equation 2x+2y=8-2x + 2y = -8.\newlineThis gives us 2(2)+2y=8-2(-2) + 2y = -8.\newlineAfter simplifying, we get 4+2y=84 + 2y = -8.
  2. Isolate 2y2y: Next, we subtract 44 from both sides of the equation to isolate 2y2y.\newlineThis gives us 2y=842y = -8 - 4.\newlineAfter simplifying, we get 2y=122y = -12.
  3. Solve for y: Finally, we divide both sides of the equation by 22 to solve for yy.\newlineThis gives us y=12/2y = -12 / 2.\newlineAfter simplifying, we get y=6y = -6.
  4. Coordinate point: We found x=2x = -2 and y=6y = -6. Substitute these values in (x,y)(x, y) to get the coordinate point.\newlineThis gives us the coordinate point (2,6)(-2, -6).

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