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Is (1,1)(1,1) a solution to this system of equations? \newline4x+10y=144x + 10y = 14\newlinex+6y=7x + 6y = 7\newlineChoices:\newline(A) yes \newline(B) no

Full solution

Q. Is (1,1)(1,1) a solution to this system of equations? \newline4x+10y=144x + 10y = 14\newlinex+6y=7x + 6y = 7\newlineChoices:\newline(A) yes \newline(B) no
  1. Substitute and check first equation: Substitute the point (1,1)(1,1) into the first equation, 4x+10y=144x + 10y = 14, to check if it holds true. Substituting x=1x=1 and y=1y=1 gives us 4(1)+10(1)4(1) + 10(1).
  2. Calculate first equation: Perform the calculation for the first equation: 4(1)+10(1)=4+10=144(1) + 10(1) = 4 + 10 = 14, which matches the right side of the equation, so the point (1,1)(1,1) satisfies the first equation.
  3. Substitute and check second equation: Substitute the point (1,1)(1,1) into the second equation, x+6y=7x + 6y = 7, to check if it holds true. Substituting x=1x=1 and y=1y=1 gives us 1(1)+6(1)1(1) + 6(1).
  4. Calculate second equation: Perform the calculation for the second equation: 1(1)+6(1)=1+6=71(1) + 6(1) = 1 + 6 = 7, which matches the right side of the equation, so the point (1,1)(1,1) satisfies the second equation as well.
  5. Conclusion: Since the point (1,1)(1,1) satisfies both the first and the second equations, we can conclude that (1,1)(1,1) is indeed a solution to the system of equations.

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