Q. Solve the system of equations by substitution.−3x−y−3z=−11z=5x−y+3z=19(____.____,____)
Substitute z=5: Substitute z=5 into the first equation −3x−y−3z=−11. −3x−y−3×5=−11 −3x−y−15=−11 −3x−y=4
Substitute z=5: Substitute z=5 into the second equation x−y+3z=19. x−y+3×5=19 x−y+15=19 x−y=4
Set equations equal: Notice that both equations −3x−y=4 and x−y=4 have the same y-term. We can use this to solve for x by setting the equations equal to each other.−3x−y=x−y−3x=x−4x=0x=0
Solve for x: Substitute x=0 into one of the equations to solve for y. We'll use x−y=4.0−y=4−y=4y=−4
Find y and z: We have already been given z=5, and we have found x=0 and y=−4. The solution is the ordered triple (x,y,z).The solution is (0,−4,5).
More problems from Solve a system of equations in three variables using substitution