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x^2(x-2)(x+3)^2<0

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Q. x2(x2)(x+3)2<0x^2(x-2)(x+3)^2<0
  1. Identify Critical Points: Identify the critical points of the inequality by setting each factor equal to zero.\newlinex2=0x^2 = 0 gives x=0x = 0\newline(x2)=0(x - 2) = 0 gives x=2x = 2\newline(x+3)2=0(x + 3)^2 = 0 gives x=3x = -3
  2. Plot on Number Line: Plot the critical points on a number line and determine the intervals to test.\newlineThe critical points divide the number line into four intervals: (,3)(-\infty, -3), (3,0)(-3, 0), (0,2)(0, 2), and (2,)(2, \infty).
  3. Choose Test Points: Choose test points from each interval and plug them into the inequality to determine the sign of the expression in that interval.\newlineFor (,3)(-\infty, -3), choose x=4x = -4: (-4)^2(-4 - 2)(-4 + 3)^2 > 0, which is positive.\newlineFor (3,0)(-3, 0), choose x=1x = -1: (-1)^2(-1 - 2)(-1 + 3)^2 < 0, which is negative.\newlineFor (0,2)(0, 2), choose x=1x = 1: (1)^2(1 - 2)(1 + 3)^2 < 0, which is negative.\newlineFor (2,)(2, \infty), choose x=4x = -400: x=4x = -411, which is positive.
  4. Determine Satisfied Intervals: Determine the intervals where the inequality is satisfied.\newlineThe inequality is satisfied in the intervals where the expression is negative, which are (3,0)(-3, 0) and (0,2)(0, 2).
  5. Consider Critical Points: Consider the behavior at the critical points. Since the inequality is strict (<0), the critical points themselves are not included in the solution.
  6. Combine Intervals: Combine the intervals to express the solution.\newlineThe solution to the inequality is the union of the intervals where the expression is negative, which is (3,0)(0,2)(-3, 0) \cup (0, 2).

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