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{:[-2x+by=59],[5x-y=1]:}
If the system of equations has exactly one solution 
(x,y) and 
x=2, what is the value of 
b ?

2x+by=59 -2 x+b y=59 \newline5xy=1 5 x-y=1 \newlineIf the system of equations has exactly one solution (x,y) (x, y) and x=2 x=2 , what is the value of b b ?

Full solution

Q. 2x+by=59 -2 x+b y=59 \newline5xy=1 5 x-y=1 \newlineIf the system of equations has exactly one solution (x,y) (x, y) and x=2 x=2 , what is the value of b b ?
  1. Find y value: Substitute x=2x=2 into the second equation to find the value of y.5xy=15x - y = 15(2)y=15(2) - y = 110y=110 - y = 1y=101y = 10 - 1y=9y = 9
  2. Find b value: Substitute x=2x=2 and y=9y=9 into the first equation to find the value of b.\newline2x+by=59-2x + by = 59\newline2(2)+b(9)=59-2(2) + b(9) = 59\newline4+9b=59-4 + 9b = 59\newline9b=59+49b = 59 + 4\newline9b=639b = 63
  3. Solve for b: Solve for b.\newline9b=639b = 63\newlineb=639b = \frac{63}{9}\newlineb=7b = 7

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