Evaluate. (root(3)(2))/(root(3)(-128))=

Understand the problem: Understand the problem. We need to find the value of the cube root of 2 divided by the cube root of -128.Apply cube root: Apply the cube root to both the numerator and the denominator. (root(3)(2))/(root(3)(-128)) = root(3)(2 / -128)Simplify fraction: Simplify the fraction inside the cube root. 2 / -128 can be simplified to -1 / 64 because 2 divided by 128 is 1/64 and we keep the negative sign. root(3)(2 / -128) = root(3)(-1 / 64)Evaluate cube root: Evaluate the cube root of -1/64. The cube root of -1 is -1 because (-1) * (-1) * (-1) = -1. The cube root of 64 is 4 because 4 * 4 * 4 = 64. Therefore, root(3)(-1 / 64) = -1 / 4.

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Evaluate.

(root(3)(2))/(root(3)(-128))=

Evaluate. $\newline$ $\frac{\sqrt[3]{2}}{\sqrt[3]{-128}}=$

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Algebra 1

Solve advanced linear inequalities

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Q. Evaluate.

\newline

\frac{\sqrt[3]{2}}{\sqrt[3]{-128}}=

Understand the problem: Understand the problem. $\newline$ We need to find the value of the cube root of $2$ divided by the cube root of $-128$ .
Apply cube root: Apply the cube root to both the numerator and the denominator. $\frac{\sqrt[3]{2}}{\sqrt[3]{-128}} = \sqrt[3]{\frac{2}{-128}}$
Simplify fraction: Simplify the fraction inside the cube root. $\newline$ $\frac{2}{-128}$ can be simplified to $-\frac{1}{64}$ because $2$ divided by $128$ is $\frac{1}{64}$ and we keep the negative sign. $\newline$ $\sqrt[3]{\frac{2}{-128}} = \sqrt[3]{-\frac{1}{64}}$
Evaluate cube root: Evaluate the cube root of $-\frac{1}{64}$ . The cube root of $-1$ is $-1$ because $(-1) \times (-1) \times (-1) = -1$ . The cube root of $64$ is $4$ because $4 \times 4 \times 4 = 64$ . Therefore, $\sqrt[3]{-\frac{1}{64}} = -\frac{1}{4}$ .