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Solve for 
z.

12=15(z-(1)/(5))

Solve for z z .\newline12=15(z15) 12=15\left(z-\frac{1}{5}\right)

Full solution

Q. Solve for z z .\newline12=15(z15) 12=15\left(z-\frac{1}{5}\right)
  1. Distribute 1515 to terms: First, we need to isolate the term containing zz on one side of the equation. We can start by distributing the 1515 to both terms inside the parentheses.\newlineCalculation: 12=15(z)15(15)12 = 15(z) - 15(\frac{1}{5})\newlineMath error check:
  2. Simplify right side: Now, simplify the right side of the equation by multiplying 1515 with 15\frac{1}{5}.\newlineCalculation: 12=15z312 = 15z - 3\newlineMath error check:
  3. Add 33 to both sides: Next, we want to get all the terms with zz on one side and the constants on the other side. We can do this by adding 33 to both sides of the equation.\newlineCalculation: 12+3=15z3+312 + 3 = 15z - 3 + 3\newlineMath error check:
  4. Combine like terms: Simplify the equation by combining like terms.\newlineCalculation: 15=15z15 = 15z\newlineMath error check:
  5. Divide by 1515: Finally, we will divide both sides of the equation by 1515 to solve for zz.\newlineCalculation: 1515=15z15\frac{15}{15} = \frac{15z}{15}\newlineMath error check:
  6. Find value of z: Simplify the equation to find the value of zz.\newlineCalculation: 1=z1 = z\newlineMath error check:

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