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Write a system of equations to describe the situation below, solve using elimination, and fill in the blanks.\newlineAt a historical landmark, candles are used to simulate an authentic atmosphere. A volunteer is currently putting new candles in the candle holders. On the east side, he replaced candles in 77 small candle holders and 33 large candle holders, using a total of 4545 candles. On the west side, he replaced the candles in 1919 small candle holders and 1919 large candle holders, for a total of 209209 candles. How many candles does each candle holder hold?\newlineEach small candleholder holds _\_ candles, and each large one holds _\_ candles.

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Q. Write a system of equations to describe the situation below, solve using elimination, and fill in the blanks.\newlineAt a historical landmark, candles are used to simulate an authentic atmosphere. A volunteer is currently putting new candles in the candle holders. On the east side, he replaced candles in 77 small candle holders and 33 large candle holders, using a total of 4545 candles. On the west side, he replaced the candles in 1919 small candle holders and 1919 large candle holders, for a total of 209209 candles. How many candles does each candle holder hold?\newlineEach small candleholder holds _\_ candles, and each large one holds _\_ candles.
  1. Equation 11: Let's denote the number of candles a small candle holder holds as ss and the number of candles a large candle holder holds as ll. The volunteer replaced candles in 77 small candle holders and 33 large candle holders on the east side, using a total of 4545 candles. This gives us the equation 7s+3l=457s + 3l = 45.
  2. Equation 22: On the west side, the volunteer replaced the candles in 1919 small candle holders and 1919 large candle holders, for a total of 209209 candles. This gives us the equation 19s+19l=20919s + 19l = 209.
  3. Eliminate Variable: We now have a system of two equations. We need to eliminate one of the variables, ss or ll. We choose to eliminate ll because its coefficients are the same in both equations.\newlineStep 44: To eliminate ll, we can subtract the first equation from the second equation. This gives us 19s+19l−(7s+3l)=209−4519s + 19l - (7s + 3l) = 209 - 45. Simplifying this, we get 12s+16l=16412s + 16l = 164.

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