Write a system of equations to describe the situation below, solve using elimination, and fill in the blanks.A local service organization is wrapping gifts at the mall to raise money for charity. Yesterday, they wrapped 22 small gifts and 21 large gifts, earning a total of $191. Today, they wrapped 18 small gifts and 10 large gifts, and earned $106. How much did they charge to wrap the gifts?The organization charges _____ to wrap a small gift and _____ to wrap a large one.
Q. Write a system of equations to describe the situation below, solve using elimination, and fill in the blanks.A local service organization is wrapping gifts at the mall to raise money for charity. Yesterday, they wrapped 22 small gifts and 21 large gifts, earning a total of $191. Today, they wrapped 18 small gifts and 10 large gifts, and earned $106. How much did they charge to wrap the gifts?The organization charges _____ to wrap a small gift and _____ to wrap a large one.
Equations setup: Let's denote the charge for wrapping a small gift as s and for a large gift as l. We can write two equations based on the given information:1. For yesterday's earnings: 22s+21l=1912. For today's earnings: 18s+10l=106These two equations form our system of equations.
Elimination method: To solve this system using elimination, we need to eliminate one of the variables. We can do this by multiplying the second equation by a number that will make the coefficient of one of the variables the same in both equations. Let's multiply the second equation by 2 to match the coefficient of l in the first equation:2×(18s+10l)=2×106This gives us:36s+20l=212
Coefficient matching: Now we have the system of equations:1. 22s+21l=1912. 36s+20l=212We can subtract the first equation from the second to eliminate l:(36s+20l)−(22s+21l)=212−191This simplifies to:14s−l=21
Subtraction correction: We made a mistake in the previous step. We should have subtracted the coefficients correctly. Let's correct that:(36s+20l)−(22s+21l)=212−191This simplifies to:14s−l=21This is incorrect. We need to subtract the l terms correctly.
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