Write a system of equations to describe the situation below, solve using elimination, and fill in the blanks.Two friends visited a taffy shop. Tanvi bought 5 kilograms of strawberry taffy and 5 kilograms of banana taffy for $65. Next, Albert bought 5 kilograms of strawberry taffy and 1 kilogram of banana taffy for $41. How much does the candy cost?A kilogram of strawberry taffy costs $_____, and a kilogram of banana taffy costs $_____.
Q. Write a system of equations to describe the situation below, solve using elimination, and fill in the blanks.Two friends visited a taffy shop. Tanvi bought 5 kilograms of strawberry taffy and 5 kilograms of banana taffy for $65. Next, Albert bought 5 kilograms of strawberry taffy and 1 kilogram of banana taffy for $41. How much does the candy cost?A kilogram of strawberry taffy costs $_____, and a kilogram of banana taffy costs $_____.
Equations Setup: Let's denote the cost of a kilogram of strawberry taffy as S dollars and the cost of a kilogram of banana taffy as B dollars. We can write two equations based on the information given:For Tanvi: 5S+5B=65 (Equation 1)For Albert: 5S+1B=41 (Equation 2)We will use these equations to solve for S and B using the elimination method.
Elimination Method: To eliminate one of the variables, we can multiply Equation 2 by −5 and add it to Equation 1 to eliminate S.Multiplying Equation 2 by −5 gives us: −25S−5B=−205 (Equation 3)
Combine Equations: Now we add Equation 1 and Equation 3:(5S+5B)+(−25S−5B)=65+(−205)This simplifies to: −20S=−140
Solve for S: We divide both sides of the equation by −20 to solve for S:−20S/−20=−140/−20S=7So, a kilogram of strawberry taffy costs $7.
Substitute S into Equation: Now that we have the value for S, we can substitute it back into Equation 2 to solve for B:5(7)+1B=4135+B=41
Final Solution: Subtracting 35 from both sides gives us:B=41−35B=6So, a kilogram of banana taffy costs $6.
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