Write a system of equations to describe the situation below, solve using elimination, and fill in the blanks.At a community barbecue, Mrs. Davidson and Mr. Ayala are buying dinner for their families. Mrs. Davidson purchases 2 hot dog meals and 3 hamburger meals, paying a total of $39. Mr. Ayala buys 3 hot dog meals and 3 hamburger meals, spending $45 in all. How much do the meals cost?Hot dog meals cost $_____ each, and hamburger meals cost $_____ each.
Q. Write a system of equations to describe the situation below, solve using elimination, and fill in the blanks.At a community barbecue, Mrs. Davidson and Mr. Ayala are buying dinner for their families. Mrs. Davidson purchases 2 hot dog meals and 3 hamburger meals, paying a total of $39. Mr. Ayala buys 3 hot dog meals and 3 hamburger meals, spending $45 in all. How much do the meals cost?Hot dog meals cost $_____ each, and hamburger meals cost $_____ each.
Define Prices: Let's denote the price of each hot dog meal as h and the price of each hamburger meal as d. Mrs. Davidson purchased 2 hot dog meals and 3 hamburger meals for a total of $39. This gives us the equation 2h+3d=39.
Mrs. Davidson's Purchase: Mr. Ayala purchased 3 hot dog meals and 3 hamburger meals for a total of $45. This gives us the equation 3h+3d=45.
Eliminate Variable: We now have a system of two equations. We need to eliminate one of the variables, h or d. We choose to eliminate h because its coefficients are the same in both equations.
Adjust Equations: To eliminate h, we multiply the first equation by −23 to match the coefficient of h in the second equation. This gives us the new equation −3h−4.5d=−58.5.
Solve for d: We now add the new first equation to the second equation to eliminate h. This gives us −1.5d=−13.5, or d=9 after dividing both sides by −1.5.
Solve for h: We substitute d=9 into the first equation and solve for h. This gives us 2h+27=39, or 2h=12 after subtracting 27 from both sides, and finally h=6 after dividing both sides by 2.
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