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Write a system of equations to describe the situation below, solve using elimination, and fill in the blanks.\newlineScouting troops in Carroll County are putting on a crab feed to raise money for camp. They offer a complete crab dinner as well as a vegetarian option. One troop member sold tickets for 1818 crab meals and 3838 vegetarian meals, with total receipts of $1,546\$1,546. Another sold tickets for 3030 crab meals and 3030 vegetarian meals, bringing in a total of $1,710\$1,710. How much do the two types of tickets cost?\newlineA ticket for a crab meal costs $____\$\_\_\_\_, and a ticket for a vegetarian meal costs $____\$\_\_\_\_.

Full solution

Q. Write a system of equations to describe the situation below, solve using elimination, and fill in the blanks.\newlineScouting troops in Carroll County are putting on a crab feed to raise money for camp. They offer a complete crab dinner as well as a vegetarian option. One troop member sold tickets for 1818 crab meals and 3838 vegetarian meals, with total receipts of $1,546\$1,546. Another sold tickets for 3030 crab meals and 3030 vegetarian meals, bringing in a total of $1,710\$1,710. How much do the two types of tickets cost?\newlineA ticket for a crab meal costs $____\$\_\_\_\_, and a ticket for a vegetarian meal costs $____\$\_\_\_\_.
  1. Define variables: Let's define the variables: Let xx be the price of a crab meal ticket, and yy be the price of a vegetarian meal ticket.
  2. Write equations: Write the equations based on the information given: \newline11st troop member: 18x+38y=154618x + 38y = 1546 \newline22nd troop member: 30x+30y=171030x + 30y = 1710
  3. Multiply and align coefficients: Multiply the first equation by 3030 and the second by 1818 to align the coefficients for elimination:\newline11st equation: 540x+1140y=46380540x + 1140y = 46380\newline22nd equation: 540x+540y=30780540x + 540y = 30780
  4. Eliminate xx: Subtract the second equation from the first to eliminate xx:540x+1140y(540x+540y)=4638030780540x + 1140y - (540x + 540y) = 46380 - 30780600y=15600600y = 15600
  5. Solve for y: Solve for y:\newliney=15600600y = \frac{15600}{600}\newliney=26y = 26
  6. Substitute and find xx: Substitute y=26y = 26 back into the second original equation to find xx:30x+30(26)=171030x + 30(26) = 171030x+780=171030x + 780 = 1710
  7. Solve for x: Solve for x:\newline30x=171078030x = 1710 - 780\newline30x=93030x = 930\newlinex=93030x = \frac{930}{30}\newlinex=31x = 31

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