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Write a system of equations to describe the situation below, solve using an augmented matrix, and fill in the blanks.\newlineThe postal service offers flat-rate shipping for priority mail in special boxes. Today, Irma shipped 11 large box, which cost her $14\$14 to ship. Meanwhile, Britney shipped 66 small boxes and 77 large boxes, and paid $140\$140. How much does it cost to ship these two sizes of box?\newlineShipping costs $\$_____ for a small box and $\$_____ for a large box.

Full solution

Q. Write a system of equations to describe the situation below, solve using an augmented matrix, and fill in the blanks.\newlineThe postal service offers flat-rate shipping for priority mail in special boxes. Today, Irma shipped 11 large box, which cost her $14\$14 to ship. Meanwhile, Britney shipped 66 small boxes and 77 large boxes, and paid $140\$140. How much does it cost to ship these two sizes of box?\newlineShipping costs $\$_____ for a small box and $\$_____ for a large box.
  1. Set up equations: Let's set up two equations to represent the costs. Let xx be the cost of a small box and yy be the cost of a large box. Irma's shipment gives us the equation y=14y = 14. Britney's shipment gives us the equation 6x+7y=1406x + 7y = 140.
  2. Write system of equations: Now we'll write the system of equations:\newline11. y=14y = 14\newline22. 6x+7y=1406x + 7y = 140
  3. Convert to matrix form: To solve using an augmented matrix, we'll convert the system of equations into matrix form. The matrix will look like this:\newline\begin{array}{cc|c} 0 & 1 & 14 \ 6 & 7 & 140 \end{array}
  4. Eliminate variable yy: We need to use the first equation to eliminate the yy variable from the second equation in the matrix. But since the first equation already has yy isolated and the coefficient is 11, we can just multiply the first row by 7-7 and add it to the second row to eliminate yy from the second equation.
  5. Perform row operation: After performing the row operation, our matrix should now look like this:\newline0amp;1amp;amp;14 6amp;0amp;amp;140(7×14)\begin{matrix} 0 & 1 & | & 14 \ 6 & 0 & | & 140 - (7 \times 14) \end{matrix}

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