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Write a system of equations to describe the situation below, solve using an augmented matrix, and fill in the blanks.\newlineBritney is a costume designer for the local children's theater company. Yesterday, she sewed 55 female costumes and 11 male costume, which used 4545 meters of fabric. Today, she sewed 11 male costume, which used a total of 55 meters. How many meters of fabric does each type of costume require?\newlineEach female costume requires ____\_\_\_\_ meters of fabric, and every male costume requires ____\_\_\_\_ meters.

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Q. Write a system of equations to describe the situation below, solve using an augmented matrix, and fill in the blanks.\newlineBritney is a costume designer for the local children's theater company. Yesterday, she sewed 55 female costumes and 11 male costume, which used 4545 meters of fabric. Today, she sewed 11 male costume, which used a total of 55 meters. How many meters of fabric does each type of costume require?\newlineEach female costume requires ____\_\_\_\_ meters of fabric, and every male costume requires ____\_\_\_\_ meters.
  1. Set Equations: Let xx be the meters of fabric for each female costume and yy for each male costume.\newlineWe get two equations:\newline5x+y=455x + y = 45 (from the first day)\newlinex+y=5x + y = 5 (from the second day)
  2. Augmented Matrix: Write the system of equations as an augmented matrix: (5amp;1 1amp;1)(x y)=(45 5)\begin{pmatrix} 5 & 1 \ 1 & 1 \end{pmatrix}\begin{pmatrix} x \ y \end{pmatrix} = \begin{pmatrix} 45 \ 5 \end{pmatrix}
  3. Row Operations: To solve the matrix, we'll use row operations to get it into reduced row-echelon form.\newlineFirst, we'll make the element in the first row, first column a 11 by dividing the entire first row by 55.\newlineamp;(1amp;0.2 1amp;1)(x y)=(9 5)\begin{align*} &\begin{pmatrix} 1 & 0.2 \ 1 & 1 \end{pmatrix} \begin{pmatrix} x \ y \end{pmatrix} = \begin{pmatrix} 9 \ 5 \end{pmatrix} \end{align*}
  4. Subtract Rows: Next, subtract the first row from the second row to make the element in the second row, first column a 00. \newlineamp;(1amp;0.2 0amp;0.8)(x y)=(9 4)\begin{align*} &\begin{pmatrix} 1 & 0.2 \ 0 & 0.8 \end{pmatrix} \begin{pmatrix} x \ y \end{pmatrix} = \begin{pmatrix} 9 \ -4 \end{pmatrix} \end{align*}
  5. Divide Rows: Now, divide the second row by 0.80.8 to make the element in the second row, second column a 11. \newline\newline\begin{align*}\newline\left| \begin{array}{cc}\newline11 & 00.22 (\newline\)00 & 11 \newline\end{array} \right|\newline\left| \begin{array}{c}\newlinex (\newline\)y \newline\end{array} \right| = \left| \begin{array}{c}\newline99 (\newline\)5-5 \newline\end{array} \right|\newline\end{align*}\newline

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