Which ordered pair is a solution of the equation? 2x+3y=10 Choose 1 answer: (A) Only (2,2) (B) Only (1,3) (C) Both (2,2) and (1,3) (D) Neither

Substitute (2,2) into equation: First, we will substitute the ordered pair (2,2) into the equation 2x+3y=10 and check if it holds true. If we substitute x=2 and y=2, we get 2*2 + 3*2 = 10. Check if it holds true: After performing the calculation, we find that 4 + 6 = 10, which is true. Therefore, the ordered pair (2,2) is a solution to the equation. Substitute (1,3) into equation: Next, we will substitute the ordered pair (1,3) into the equation 2x+3y=10 and check if it holds true. If we substitute x=1 and y=3, we get 2*1 + 3*3 = 10. Check if it holds true: After performing the calculation, we find that 2 + 9 = 11, which is not equal to 10. Therefore, the ordered pair (1,3) is not a solution to the equation. Identify the solution: Since the ordered pair (2,2) is a solution and the ordered pair (1,3) is not, the correct answer is that only (2,2) is a solution to the equation.

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Which ordered pair is a solution of the equation? $\newline$ $2x+3y=10$ $\newline$ Choose $1$ answer: $\newline$ (A) Only $(2,2)$ $\newline$ (B) Only $(1,3)$ $\newline$ (C) Both $(2,2)$ and $(1,3)$ $\newline$ (D) Neither

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Algebra 2

Is (x, y) a solution to the system of equations?

Full solution

Q. Which ordered pair is a solution of the equation?

\newline

2x+3y=10

\newline

Choose

1

answer:

\newline

(A) Only

(2,2)

\newline

(B) Only

(1,3)

\newline

(2,2)

and

(1,3)

\newline

(D) Neither

Substitute $(2,2)$ into equation: First, we will substitute the ordered pair $(2,2)$ into the equation $2x+3y=10$ and check if it holds true. If we substitute $x=2$ and $y=2$ , we get $2\cdot 2 + 3\cdot 2 = 10$ .
Check if it holds true: After performing the calculation, we find that $4 + 6 = 10$ , which is true. Therefore, the ordered pair $(2,2)$ is a solution to the equation.
Substitute $(1,3)$ into equation: Next, we will substitute the ordered pair $(1,3)$ into the equation $2x+3y=10$ and check if it holds true. If we substitute $x=1$ and $y=3$ , we get $2\cdot 1 + 3\cdot 3 = 10$ .
Check if it holds true: After performing the calculation, we find that $2 + 9 = 11$ , which is not equal to $10$ . Therefore, the ordered pair $(1,3)$ is not a solution to the equation.
Identify the solution: Since the ordered pair $(2,2)$ is a solution and the ordered pair $(1,3)$ is not, the correct answer is that only $(2,2)$ is a solution to the equation.