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Which of the following functions are continuous for all real numbers?\newlineg(x)=ln(x)g(x)=\ln(x)\newlinef(x)=1xf(x)=\frac{1}{x}\newlineChoose 11 answer:\newlineA) gg only\newline(B) ff only\newline(C) Both gg and ff\newline(D) Neither gg nor ff

Full solution

Q. Which of the following functions are continuous for all real numbers?\newlineg(x)=ln(x)g(x)=\ln(x)\newlinef(x)=1xf(x)=\frac{1}{x}\newlineChoose 11 answer:\newlineA) gg only\newline(B) ff only\newline(C) Both gg and ff\newline(D) Neither gg nor ff
  1. Question Prompt: Question prompt: Determine which of the given functions, g(x)=ln(x)g(x) = \ln(x) and f(x)=1xf(x) = \frac{1}{x}, are continuous for all real numbers.
  2. Analyze g(x)=ln(x)g(x) = \ln(x): Analyze the function g(x)=ln(x)g(x) = \ln(x). The natural logarithm function ln(x)\ln(x) is defined only for x > 0. Therefore, g(x)g(x) is not continuous for all real numbers because it is not defined for x0x \leq 0.
  3. Analyze f(x)=1xf(x) = \frac{1}{x}: Analyze the function f(x)=1xf(x) = \frac{1}{x}. The function 1x\frac{1}{x} is defined for all real numbers except x=0x = 0, where it has a vertical asymptote. Therefore, f(x)f(x) is not continuous at x=0x = 0 and thus not continuous for all real numbers.
  4. Conclusion: Since neither g(x)=ln(x)g(x) = \ln(x) nor f(x)=1xf(x) = \frac{1}{x} is continuous for all real numbers, the correct answer is (D) Neither gg nor ff.

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