Which equation has the solution x=7 ? 5x+1=-36 6x+9=81 5x-2=30 4x+9=37

Identify Equation: We need to find which equation has x=7 as its solution. To do this, we will substitute x=7 into each equation and see which one holds true.Check First Equation: Substitute x=7 into the first equation 5x+1=-36. 5(7) + 1 = -36 35 + 1 = -36 36 = -36 This is not true, so the first equation does not have x=7 as its solution.Check Second Equation: Substitute x=7 into the second equation 6x+9=81. 6(7) + 9 = 81 42 + 9 = 81 51 = 81 This is not true, so the second equation does not have x=7 as its solution.Check Third Equation: Substitute x=7 into the third equation 5x-2=30. 5(7) - 2 = 30 35 - 2 = 30 33 = 30 This is not true, so the third equation does not have x=7 as its solution.Check Fourth Equation: Substitute x=7 into the fourth equation 4x+9=37. 4(7) + 9 = 37 28 + 9 = 37 37 = 37 This is true, so the fourth equation has x=7 as its solution.

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Which equation has the solution
x=7 ?

5x+1=-36

6x+9=81

5x-2=30

4x+9=37

Which equation has the solution $x=7$ ? $\newline$ $5 x+1=-36$ $\newline$ $6 x+9=81$ $\newline$ $5 x-2=30$ $\newline$ $4 x+9=37$

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Math Problems

Precalculus

Solve a system of equations in three variables using elimination

Full solution

Q. Which equation has the solution

x=7

\newline

5 x+1=-36

\newline

6 x+9=81

\newline

5 x-2=30

\newline

4 x+9=37

Identify Equation: We need to find which equation has $x=7$ as its solution. To do this, we will substitute $x=7$ into each equation and see which one holds true.
Check First Equation: Substitute $x=7$ into the first equation $5x+1=-36$ .
$5(7) + 1 = -36$
$35 + 1 = -36$
$36 = -36$
This is not true, so the first equation does not have $x=7$ as its solution.
Check Second Equation: Substitute $x=7$ into the second equation $6x+9=81$ .
$6(7) + 9 = 81$
$42 + 9 = 81$
$51 = 81$
This is not true, so the second equation does not have $x=7$ as its solution.
Check Third Equation: Substitute $x=7$ into the third equation $5x-2=30$ . $5(7) - 2 = 30$ $35 - 2 = 30$ $33 = 30$ This is not true, so the third equation does not have $x=7$ as its solution.
Check Fourth Equation: Substitute $x=7$ into the fourth equation $4x+9=37$ .
$4(7) + 9 = 37$
$28 + 9 = 37$
$37 = 37$
This is true, so the fourth equation has $x=7$ as its solution.