Which equation has the solution x=3 ? 9x-9=126 4x-2=-10 7x-6=15 2x-2=1

Find Equation Solution: We need to find the equation that has x=3 as its solution. To do this, we will substitute x=3 into each equation and see which one results in a true statement.Substitute x=3: Substitute x=3 into the first equation: 9x-9=126. Calculation: 9(3) - 9 = 27 - 9 = 18. Check if 18 equals 126: 18 ≠ 126.Check First Equation: Since 18 does not equal 126, the first equation does not have x=3 as its solution. Now, substitute x=3 into the second equation: 4x-2=-10. Calculation: 4(3) - 2 = 12 - 2 = 10. Check if 10 equals -10: 10 ≠ -10.Check Second Equation: Since 10 does not equal -10, the second equation does not have x=3 as its solution. Now, substitute x=3 into the third equation: 7x-6=15. Calculation: 7(3) - 6 = 21 - 6 = 15. Check if 15 equals 15: 15 = 15.Check Third Equation: Since 15 equals 15, the third equation has x=3 as its solution. We do not need to check the fourth equation because we have already found the correct equation.

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Which equation has the solution
x=3 ?

9x-9=126

4x-2=-10

7x-6=15

2x-2=1

Which equation has the solution $x=3$ ? $\newline$ $9 x-9=126$ $\newline$ $4 x-2=-10$ $\newline$ $7 x-6=15$ $\newline$ $2 x-2=1$

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Math Problems

Precalculus

Solve a system of equations in three variables using elimination

Full solution

Q. Which equation has the solution

x=3

\newline

9 x-9=126

\newline

4 x-2=-10

\newline

7 x-6=15

\newline

2 x-2=1

Find Equation Solution: We need to find the equation that has $x=3$ as its solution. To do this, we will substitute $x=3$ into each equation and see which one results in a true statement.
Substitute $x=3$ : Substitute $x=3$ into the first equation: $9x-9=126$ . $\newline$ Calculation: $9(3) - 9 = 27 - 9 = 18$ . $\newline$ Check if $18$ equals $126$ : $18 \neq 126$ .
Check First Equation: Since $18$ does not equal $126$ , the first equation does not have $x=3$ as its solution. Now, substitute $x=3$ into the second equation: $4x-2=-10$ . $\newline$ Calculation: $4(3) - 2 = 12 - 2 = 10$ . $\newline$ Check if $10$ equals $-10$ : $10 \neq -10$ .
Check Second Equation: Since $10$ does not equal $-10$ , the second equation does not have $x=3$ as its solution. Now, substitute $x=3$ into the third equation: $7x-6=15$ . $\newline$ Calculation: $7(3) - 6 = 21 - 6 = 15$ . $\newline$ Check if $15$ equals $15$ : $15 = 15$ .
Check Third Equation: Since $15$ equals $15$ , the third equation has $x=3$ as its solution. We do not need to check the fourth equation because we have already found the correct equation.