Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

What is the product of (1p)(1-p) and (12p)\left(\frac{1}{2}-p\right), all reduced by PP?

Full solution

Q. What is the product of (1p)(1-p) and (12p)\left(\frac{1}{2}-p\right), all reduced by PP?
  1. Multiply binomials: First, we need to multiply the two binomials (1p)(1-p) and (12p)(\frac{1}{2}-p) together.(1p)(12p)=1(12p)p(12p)(1-p)(\frac{1}{2}-p) = 1*(\frac{1}{2}-p) - p*(\frac{1}{2}-p)
  2. Distribute terms: Now, distribute the terms within the parentheses.\newline\(1\times\left(\frac{11}{22}-p\right) - p\times\left(\frac{11}{22}-p\right) = \frac{11}{22} - p - \left(\frac{p}{22}\right) + p^22
  3. Combine like terms: Combine like terms.\newline12pp2+p2=123p2+p2\frac{1}{2} - p - \frac{p}{2} + p^2 = \frac{1}{2} - \frac{3p}{2} + p^2
  4. Reduce expression by P: Now, we need to reduce this expression by P, which means we subtract P from the expression we obtained. 123p2+p2\frac{1}{2} - \frac{3p}{2} + p^2 - P
  5. Subtract P: Subtract PP from the expression.(123p2+p2)P=123p2+p2P\left(\frac{1}{2} - \frac{3p}{2} + p^2\right) - P = \frac{1}{2} - \frac{3p}{2} + p^2 - P
  6. Combine like terms with P: Combine PP with the like terms, noting that PP is the same as 1P1*P or p/1p/1. \newline123p2+p2p1=125p2+p2\frac{1}{2} - \frac{3p}{2} + p^2 - \frac{p}{1} = \frac{1}{2} - \frac{5p}{2} + p^2
  7. Final simplified expression: The final simplified expression is: 125p2+p2\frac{1}{2} - \frac{5p}{2} + p^2

More problems from Evaluate definite integrals using the chain rule