Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

Consider the following problem:
The water level under a bridge is changing at a rate of 
r(t)=40 sin((pi t)/(6)) centimeters per hour (where 
t is the time in hours). At time 
t=3, the water level is 91 centimeters. By how much does the water level change during the 
4^("th ") hour?
Which expression can we use to solve the problem?
Choose 1 answer:
(A) 
int_(3)^(4)r(t)dt
(B) 
int_(0)^(4)r(t)dt
(C) 
int_(4)^(5)r(t)dt
(D) 
int_(4)^(4)r(t)dt

Consider the following problem:\newlineThe water level under a bridge is changing at a rate of r(t)=40sin(πt6) r(t)=40 \sin \left(\frac{\pi t}{6}\right) centimeters per hour (where t t is the time in hours). At time t=3 t=3 , the water level is 9191 centimeters. By how much does the water level change during the 4th  4^{\text {th }} hour?\newlineWhich expression can we use to solve the problem?\newlineChoose 11 answer:\newline(A) 34r(t)dt \int_{3}^{4} r(t) d t \newline(B) 04r(t)dt \int_{0}^{4} r(t) d t \newline(C) 45r(t)dt \int_{4}^{5} r(t) d t \newline(D) 44r(t)dt \int_{4}^{4} r(t) d t

Full solution

Q. Consider the following problem:\newlineThe water level under a bridge is changing at a rate of r(t)=40sin(πt6) r(t)=40 \sin \left(\frac{\pi t}{6}\right) centimeters per hour (where t t is the time in hours). At time t=3 t=3 , the water level is 9191 centimeters. By how much does the water level change during the 4th  4^{\text {th }} hour?\newlineWhich expression can we use to solve the problem?\newlineChoose 11 answer:\newline(A) 34r(t)dt \int_{3}^{4} r(t) d t \newline(B) 04r(t)dt \int_{0}^{4} r(t) d t \newline(C) 45r(t)dt \int_{4}^{5} r(t) d t \newline(D) 44r(t)dt \int_{4}^{4} r(t) d t
  1. Integrate rate of change: To find the change in water level during the 4th4^{\text{th}} hour, we need to integrate the rate of change function, r(t)r(t), from the start of the 4th4^{\text{th}} hour to the end of the 4th4^{\text{th}} hour.
  2. Identify time interval: The 4th4^{\text{th}} hour starts at t=3t=3 and ends at t=4t=4. Therefore, we need to evaluate the integral of r(t)r(t) from 33 to 44.
  3. Evaluate integral expression: The correct expression to use for solving the problem is the integral of r(t)r(t) from 33 to 44, which is option (A) 34r(t)dt\int_{3}^{4}r(t)\,dt.

More problems from Evaluate definite integrals using the power rule