Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

1cos(x)2dx\int \frac{1}{\cos(x)^{2}}\,dx

Full solution

Q. 1cos(x)2dx\int \frac{1}{\cos(x)^{2}}\,dx
  1. Recognize Integral: Recognize that the integral of 1cos2(x)\frac{1}{\cos^2(x)} is a standard integral.\newlineThe function 1cos2(x)\frac{1}{\cos^2(x)} can be rewritten as sec2(x)\sec^2(x), where sec(x)\sec(x) is the secant function, which is 1cos(x)\frac{1}{\cos(x)}.
  2. Recall Antiderivative: Recall the antiderivative of sec2(x)\sec^2(x). The antiderivative of sec2(x)\sec^2(x) is a well-known result, which is the tangent function, tan(x)\tan(x). Therefore, sec2(x)dx=tan(x)+C\int \sec^2(x)\,dx = \tan(x) + C, where CC is the constant of integration.
  3. Write Final Answer: Write the final answer.\newlineThe integral of 1cos2(x)\frac{1}{\cos^2(x)} with respect to xx is tan(x)+C\tan(x) + C.

More problems from Evaluate definite integrals using the chain rule