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What is the integral of x2x^2 from 00 to 44

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Q. What is the integral of x2x^2 from 00 to 44
  1. Find Antiderivative: To solve the integral of x2x^2 from 00 to 44, we need to find the antiderivative of x2x^2 and then evaluate it at the upper and lower limits of the integral.\newlineThe antiderivative of x2x^2 is (1/3)x3(1/3)x^3, since the derivative of (1/3)x3(1/3)x^3 with respect to xx is x2x^2.\newlineCalculation: x2dx=(1/3)x3+C\int x^2 dx = (1/3)x^3 + C, where 0000 is the constant of integration.
  2. Evaluate at Limits: Now we need to evaluate the antiderivative at the upper limit of 44 and subtract the evaluation at the lower limit of 00.
    Calculation: [13×43][13×03]=13×640=643\left[\frac{1}{3} \times 4^3\right] - \left[\frac{1}{3} \times 0^3\right] = \frac{1}{3} \times 64 - 0 = \frac{64}{3}.

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