What is the average value of h(x)=(x^(3)+7x^(2)+3)/(2x^(2)-5x+4) on the interval [-8,-2] ? Use a graphing calculator and round your answer to three decimal places.

Calculate h(-8): Calculate h(-8) using the graphing calculator. h(-8) = ((-8)^3 + 7*(-8)^2 + 3) / (2*(-8)^2 - 5*(-8) + 4) h(-8) = ((-512) + 7*(64) + 3) / (2*(64) - 5*(-8) + 4) h(-8) = ((-512) + 448 + 3) / (128 + 40 + 4) h(-8) = (-61) / (172) h(-8) ≈ -0.355 (rounded to three decimal places)Calculate h(-2): Calculate h(-2) using the graphing calculator. h(-2) = ((-2)^3 + 7*(-2)^2 + 3) / (2*(-2)^2 - 5*(-2) + 4) h(-2) = ((-8) + 7*(4) + 3) / (2*(4) - 5*(-2) + 4) h(-2) = (-8 + 28 + 3) / (8 + 10 + 4) h(-2) = 23 / 22 h(-2) ≈ 1.045 (rounded to three decimal places)Find average value: Find the average value of h(x) over the interval [-8,-2]. Average value = (h(-2) - h(-8)) / (-2 - (-8)) Average value = (1.045 - (-0.355)) / (6) Average value = (1.045 + 0.355) / 6 Average value = 1.4 / 6 Average value ≈ 0.233 (rounded to three decimal places)

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What is the average value of
h(x)=(x^(3)+7x^(2)+3)/(2x^(2)-5x+4) on the interval
[-8,-2] ?
Use a graphing calculator and round your answer to three decimal places.

What is the average value of $h(x)=\frac{x^{3}+7 x^{2}+3}{2 x^{2}-5 x+4}$ on the interval $[-8,-2]$ ? $\newline$ Use a graphing calculator and round your answer to three decimal places.

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Q. What is the average value of

h(x)=\frac{x^{3}+7 x^{2}+3}{2 x^{2}-5 x+4}

on the interval

[-8,-2]

\newline

Use a graphing calculator and round your answer to three decimal places.

Calculate $h(-8)$ : Calculate $h(-8)$ using the graphing calculator. $\newline$ $h(-8) = ((-8)^3 + 7*(-8)^2 + 3) / (2*(-8)^2 - 5*(-8) + 4)$ $\newline$ $h(-8) = ((-512) + 7*(64) + 3) / (2*(64) - 5*(-8) + 4)$ $\newline$ $h(-8) = ((-512) + 448 + 3) / (128 + 40 + 4)$ $\newline$ $h(-8) = (-61) / (172)$ $\newline$ $h(-8) \approx -0.355$ (rounded to three decimal places)
Calculate $h(-2)$ : Calculate $h(-2)$ using the graphing calculator. $\newline$ $h(-2) = ((-2)^3 + 7*(-2)^2 + 3) / (2*(-2)^2 - 5*(-2) + 4)$ $\newline$ $h(-2) = ((-8) + 7*(4) + 3) / (2*(4) - 5*(-2) + 4)$ $\newline$ $h(-2) = (-8 + 28 + 3) / (8 + 10 + 4)$ $\newline$ $h(-2) = 23 / 22$ $\newline$ $h(-2) ≈ 1.045$ (rounded to three decimal places)
Find average value: Find the average value of $h(x)$ over the interval $[-8,-2]$ . $\newline$ Average value = $\frac{h(-2) - h(-8)}{-2 - (-8)}$ $\newline$ Average value = $\frac{1.045 - (-0.355)}{6}$ $\newline$ Average value = $\frac{1.045 + 0.355}{6}$ $\newline$ Average value = $\frac{1.4}{6}$ $\newline$ Average value $\approx 0.233$ (rounded to three decimal places)