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(14+60 i)+(-30+2i)= Express your answer in the form (a+bi).

(14+60i)+(−30+2i)= (14+60 i)+(-30+2 i)= \newlineExpress your answer in the form (a+bi) (a+b i) .

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Full solution

Q. (14+60i)+(−30+2i)= (14+60 i)+(-30+2 i)= \newlineExpress your answer in the form (a+bi) (a+b i) .
  1. Add real parts: Add the real parts of the complex numbers.\newlineThe real part of the first complex number is 1414, and the real part of the second complex number is −30-30.\newlineAdd these two numbers together to get the real part of the sum.\newline14+(−30)=−1614 + (-30) = -16
  2. Add imaginary parts: Add the imaginary parts of the complex numbers.\newlineThe imaginary part of the first complex number is 60i60i, and the imaginary part of the second complex number is 2i2i.\newlineAdd these two numbers together to get the imaginary part of the sum.\newline60i+2i=62i60i + 2i = 62i
  3. Combine results: Combine the results from Step 11 and Step 22 to express the sum in the form (a+bi)(a+bi).\newlineThe real part obtained from Step 11 is −16-16, and the imaginary part obtained from Step 22 is 62i62i.\newlineCombine these to get the final answer in the form (a+bi)(a+bi).\newline(−16)+(62i)=−16+62i(-16) + (62i) = -16 + 62i

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