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(-71+2i)+(88-12 i)= Express your answer in the form (a+bi).

(−71+2i)+(88−12i)= (-71+2 i)+(88-12 i)= \newlineExpress your answer in the form (a+bi) (a+b i) .

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Full solution

Q. (−71+2i)+(88−12i)= (-71+2 i)+(88-12 i)= \newlineExpress your answer in the form (a+bi) (a+b i) .
  1. Addition of Complex Numbers: To add two complex numbers, we add their real parts together and their imaginary parts together separately.\newline(−71+2i)+(88−12i)=(−71+88)+(2i−12i)(-71+2i) + (88-12i) = (-71 + 88) + (2i - 12i)
  2. Calculating the Sum of Real Parts: Now, we calculate the sum of the real parts: −71+88-71 + 88.\newline−71+88=17-71 + 88 = 17
  3. Calculating the Sum of Imaginary Parts: Next, we calculate the sum of the imaginary parts: 2i−12i2i - 12i.\newline2i−12i=−10i2i - 12i = -10i
  4. Combining the Real and Imaginary Parts: Combine the results of the real part and the imaginary part to express the answer in the form (a+bi)(a+bi).\newline17+(−10i)=17−10i17 + (-10i) = 17 - 10i

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