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(18+4i)+(-11+23 i)=
Express your answer in the form 
(a+bi).

(18+4i)+(11+23i)= (18+4 i)+(-11+23 i)= \newlineExpress your answer in the form (a+bi) (a+b i) .

Full solution

Q. (18+4i)+(11+23i)= (18+4 i)+(-11+23 i)= \newlineExpress your answer in the form (a+bi) (a+b i) .
  1. Add real parts: Add the real parts of the complex numbers.\newlineThe real part of the first complex number is 1818, and the real part of the second complex number is 11-11. Adding these together gives us:\newline18+(11)=718 + (-11) = 7
  2. Add imaginary parts: Add the imaginary parts of the complex numbers.\newlineThe imaginary part of the first complex number is 4i4i, and the imaginary part of the second complex number is 23i23i. Adding these together gives us:\newline4i+23i=27i4i + 23i = 27i
  3. Combine results: Combine the results from Step 11 and Step 22 to express the sum in the form (a+bi)(a+bi).\newlineFrom Step 11, we have the real part as 77, and from Step 22, we have the imaginary part as 27i27i. Therefore, the sum of the complex numbers is:\newline7+27i7 + 27i

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