Q. What is the average value of f(x)=ex2−2x on the interval [−1,3] ?Use a graphing calculator and round your answer to three decimal places.
Calculate Interval Width: To find the average value of f(x) over the interval [−1,3], we use the formula for the average value of a function on an interval [a,b]: Average value = (b−a)1×∫abf(x)dx. Here, a=−1 and b=3.
Set Up Integral: First, calculate the width of the interval: b−a=3−(−1)=4.
Evaluate Integral: Now, set up the integral for the average value: Average value = (41)∫−13e(x2−2x)dx.
Find Average Value: Use a graphing calculator to evaluate the integral ∫−13e(x2−2x)dx. Let's say the calculator gives us a value of Z for the integral.
Round to Three Decimals: Multiply the result of the integral by the reciprocal of the interval width to find the average value: Average value = (1/4)×Z.
Round to Three Decimals: Multiply the result of the integral by the reciprocal of the interval width to find the average value: Average value = (1/4)×Z.Round the result to three decimal places as instructed. Let's say the rounded value is Y.