Resourcesdown chevron
Testimonials
Plans
Sign in
Sign up
Resourcesright arrow
Testimonials
Plans
Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

The width of a rectangle measures (3t+1) centimeters, and its length measures (10 t+5) centimeters. Which expression represents the perimeter, in centimeters, of the rectangle? 26 t+12 8t+30 15+4t 13 t+6

The width of a rectangle measures (3t+1) (3 t+1) centimeters, and its length measures (10t+5) (10 t+5) centimeters. Which expression represents the perimeter, in centimeters, of the rectangle?\newline26t+12 26 t+12 \newline8t+30 8 t+30 \newline15+4t 15+4 t \newline13t+6 13 t+6

View step-by-step helpView step-by-step help
Homeright chevron icon
Math Problemsright chevron icon
Calculusright chevron icon
Evaluate definite integrals using the chain ruleright chevron icon

Full solution

Q. The width of a rectangle measures (3t+1) (3 t+1) centimeters, and its length measures (10t+5) (10 t+5) centimeters. Which expression represents the perimeter, in centimeters, of the rectangle?\newline26t+12 26 t+12 \newline8t+30 8 t+30 \newline15+4t 15+4 t \newline13t+6 13 t+6
  1. Perimeter Formula: The perimeter of a rectangle is calculated by adding together twice the width and twice the length. The formula for the perimeter PP of a rectangle is P=2×width+2×lengthP = 2 \times \text{width} + 2 \times \text{length}.
  2. Substitute Values: Given the width ww is 3t+13t+1 centimeters and the length ll is 10t+510t+5 centimeters, we can substitute these values into the perimeter formula: P=2×(3t+1)+2×(10t+5)P = 2 \times (3t+1) + 2 \times (10t+5).
  3. Distribute 22: Now we distribute the 22 into each term inside the parentheses: P=2×3t+2×1+2×10t+2×5P = 2 \times 3t + 2 \times 1 + 2 \times 10t + 2 \times 5.
  4. Perform Multiplication: Perform the multiplication: P=6t+2+20t+10P = 6t + 2 + 20t + 10.
  5. Combine Like Terms: Combine like terms: P=(6t+20t)+(2+10)P = (6t + 20t) + (2 + 10).
  6. Add Like Terms: Add the like terms: P=26t+12P = 26t + 12.
  7. Final Expression: The expression that represents the perimeter of the rectangle in centimeters is 26t+1226t + 12.

More problems from Evaluate definite integrals using the chain rule

Question
Consider the following problem:\newlineThe water level under a bridge is changing at a rate of r(t)=40sin⁡(πt6) r(t)=40 \sin \left(\frac{\pi t}{6}\right) centimeters per hour (where t t is the time in hours). At time t=3 t=3 , the water level is 9191 centimeters. By how much does the water level change during the 4th  4^{\text {th }} hour?\newlineWhich expression can we use to solve the problem?\newlineChoose 11 answer:\newline(A) ∫34r(t)dt \int_{3}^{4} r(t) d t \newline(B) ∫04r(t)dt \int_{0}^{4} r(t) d t \newline(C) ∫45r(t)dt \int_{4}^{5} r(t) d t \newline(D) ∫44r(t)dt \int_{4}^{4} r(t) d t
Get tutor helpright-arrow

Posted 8 months ago

Question
The function s(t) s(t) gives the number of students enrolled in a school by time t t (in years).\newlineWhat does ∫1518s′(t)dt=20 \int_{15}^{18} s^{\prime}(t) d t=20 mean?\newlineChoose 11 answer:\newline(A) The rate of change of enrollment is 2020 students per year more in year 1818 than it was in year 1515.\newline(B) There were 2020 more students enrolled in year 1818 than in year 1515 .\newline(C) Between years 1515 and 1818, the cumulative number of years of schooling of all of the enrolled students is 2020 years.\newline(D) There are 2020 students enrolled in year 1818.
Get tutor helpright-arrow

Posted 7 months ago

Question
A water tank is filled at a rate of r(t) r(t) liters per minute (where t t is the time in minutes).\newlineWhat does ∫17r′(t)dt \int_{1}^{7} r^{\prime}(t) d t represent?\newlineChoose 11 answer:\newline(A) The rate at which the tank was filled at t=7 t=7 .\newlineB) The average rate of filling between t=1 t=1 and t=7 t=7 .\newline(C) The change in the rate of filling between t=1 t=1 and t=7 t=7 .\newline(D) The amount of water filled between t=1 t=1 and t=7 t=7 .
Get tutor helpright-arrow

Posted 8 months ago

Question
The base of a solid is the region enclosed by the graphs of y=sin⁡(x) y=\sin (x) and y=4−x y=4-\sqrt{x} , between x=2 x=2 and x=7 x=7 .\newlineCross sections of the solid perpendicular to the x x -axis are rectangles whose height is 2x 2 x .\newlineWhich one of the definite integrals gives the volume of the solid?\newlineChoose 11 answer:\newline(A) ∫27[(4−x)2−sin⁡2(x)]dx \int_{2}^{7}\left[(4-\sqrt{x})^{2}-\sin ^{2}(x)\right] d x \newline(B) ∫27[sin⁡(x)+x−4]⋅2xdx \int_{2}^{7}[\sin (x)+\sqrt{x}-4] \cdot 2 x d x \newline(C) ∫27[sin⁡2(x)−(4−x)2]dx \int_{2}^{7}\left[\sin ^{2}(x)-(4-\sqrt{x})^{2}\right] d x \newline(D) ∫27[4−x−sin⁡(x)]⋅2xdx \int_{2}^{7}[4-\sqrt{x}-\sin (x)] \cdot 2 x d x
Get tutor helpright-arrow

Posted 8 months ago

Question
Evaluate the integral.\newline∫−2x3cos⁡(3x)dx \int-2 x^{3} \cos (3 x) d x \newlineAnswer:
Get tutor helpright-arrow

Posted 9 months ago

Question
Evaluate the integral.\newline∫−4x233xdx \int-4 x^{2} 3^{3 x} d x \newlineAnswer:
Get tutor helpright-arrow

Posted 9 months ago

Question
Evaluate the integral.\newline∫−4x2e4xdx \int-4 x^{2} e^{4 x} d x \newlineAnswer:
Get tutor helpright-arrow

Posted 9 months ago

Question
∑n=1∞3nn2n!\sum_{n=1}^{\infty}\frac{3^{n}n^{2}}{n!}
Get tutor helpright-arrow

Posted 8 months ago

Question
f)lim⁡n→+∞[2n+(35)n] f) \lim_{n \to +\infty}\left[\frac{2}{n}+\left(\frac{3}{5}\right)^n\right]
Get tutor helpright-arrow

Posted 8 months ago

Question
∫1cos⁡(x)2 dx\int \frac{1}{\cos(x)^{2}}\,dx
Get tutor helpright-arrow

Posted 8 months ago

View all (198)

Related topics

Algebra - Order of OperationsAlgebra - Distributive Property`X` and `Y` AxesGeometry - Scalene TriangleCommon MultipleGeometry - Quadrant