The graph of a line in the xy-plane has a slope of and contains the point (1,−5). The graph of a second line passes through the points (0,4) and (12,0). If the two lines intersect at the point (a,b) what is the value of a−b?
Q. The graph of a line in the xy-plane has a slope of and contains the point (1,−5). The graph of a second line passes through the points (0,4) and (12,0). If the two lines intersect at the point (a,b) what is the value of a−b?
Find First Line Equation: First, let's find the equation of the first line with the given slope m and point (1,−5). The slope-intercept form of a line is y=mx+b, where m is the slope and b is the y-intercept. We are given the slope m=(slope not provided in the problem, assuming it’s a typo and should be a number), and we have the point (1,−5). Let's plug in the values into the equation y=mx+b to find b. −5=m×1+b(1,−5)0(1,−5)1
Find Second Line Equation: Now, let's find the equation of the second line that passes through the points (0,4) and (12,0). The slope m of a line passing through two points (x1,y1) and (x2,y2) is given by m=x2−x1y2−y1. For the points (0,4) and (12,0), the slope m is: m=12−00−4(12,0)0(12,0)1
Intersection Point Calculation: Since the second line passes through the point (0,4), which is the y-intercept, the equation of the second line is:y=(−31)x+4
Intersection Point Calculation: Since the second line passes through the point (0,4), which is the y-intercept, the equation of the second line is:y=(−31)x+4To find the intersection point (a,b) of the two lines, we need to set their equations equal to each other.However, we have an issue: the slope of the first line was not provided in the problem statement. Without this information, we cannot find the equation of the first line and therefore cannot find the intersection point.This is a critical piece of information missing, and we cannot proceed without it.
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