Solve. –x + 7y = 7 x = 7 (_____, _____)

Substitute x = 7: First, we substitute x = 7 into the equation –x + 7y = 7. This gives us –(7) + 7y = 7. After simplifying, we get -7 + 7y = 7.Add to isolate 7y: Next, we add 7 to both sides of the equation to isolate 7y. This gives us 7y = 7 + 7. After simplifying, we get 7y = 14.Divide to solve for y: Finally, we divide both sides of the equation by 7 to solve for y. This gives us y = 14 / 7. After simplifying, we get y = 2.Substitute values for coordinate point: We found x = 7 and y = 2. Substitute these values in (x , y) to get the coordinate point. This gives us the coordinate point (7, 2).

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Solve. $\newline$ $-x + 7y = 7$ $\newline$ $x = 7$ $\newline$ (_, _)

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Algebra 2

Solve a system of equations using any method

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Q. Solve.

\newline

-x + 7y = 7

\newline

x = 7

\newline

(_____, _____)

Substitute $x = 7$ : First, we substitute $x = 7$ into the equation $–x + 7y = 7$ . This gives us $–(7) + 7y = 7$ . After simplifying, we get $-7 + 7y = 7$ .
Add to isolate $7y$ : Next, we add $7$ to both sides of the equation to isolate $7y$ . This gives us $7y = 7 + 7$ . After simplifying, we get $7y = 14$ .
Divide to solve for $y$ : Finally, we divide both sides of the equation by $7$ to solve for $y$ . This gives us $y = \frac{14}{7}$ . After simplifying, we get $y = 2$ .
Substitute values for coordinate point: We found $x = 7$ and $y = 2$ . Substitute these values in $(x , y)$ to get the coordinate point. $\newline$ This gives us the coordinate point $(7, 2)$ .