Solve. x + 6y = –4 x = –10 (_____, _____)

Substitute x = -10: First, we substitute x = -10 into the equation x + 6y = -4. This gives us -10 + 6y = -4.Add 10 to isolate y: Next, we add 10 to both sides of the equation to isolate the term with y. This gives us 6y = -4 + 10. After simplifying, we get 6y = 6.Divide by 6 for y: Finally, we divide both sides of the equation by 6 to solve for y. This gives us y = 6 / 6. After simplifying, we get y = 1.Substitute values for point: We found x = -10 and y = 1. Substitute these values in (x , y) to get the coordinate point. This gives us the coordinate point (-10, 1).

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Solve. $\newline$ $x + 6y = -4$ $\newline$ $x = -10$ $\newline$ (_, _)

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Algebra 2

Solve a system of equations using any method

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Q. Solve.

\newline

x + 6y = -4

\newline

x = -10

\newline

(_____, _____)

Substitute $x = -10$ : First, we substitute $x = -10$ into the equation $x + 6y = -4$ . This gives us $-10 + 6y = -4$ .
Add $10$ to isolate $y$ : Next, we add $10$ to both sides of the equation to isolate the term with $y$ . This gives us $6y = -4 + 10$ . After simplifying, we get $6y = 6$ .
Divide by $6$ for y: Finally, we divide both sides of the equation by $6$ to solve for $y$ . This gives us $y = \frac{6}{6}$ . After simplifying, we get $y = 1$ .
Substitute values for point: We found $x = -10$ and $y = 1$ . Substitute these values in $(x , y)$ to get the coordinate point. $\newline$ This gives us the coordinate point $(-10, 1)$ .