Solve using substitution. y = –7 7x − 8y = 7 (_____, _____)

Given value of y: First, we are given the value of y, which is -7. We need to substitute this value into the second equation to find the value of x. y = –7 7x − 8y = 7 Substitute y = -7 into the second equation: 7x - 8(-7) = 7Substitute y into equation: Now, we simplify the equation by multiplying -8 with -7 and then solve for x. 7x + 56 = 7Simplify and solve for x: Next, we subtract 56 from both sides of the equation to isolate the term with x. 7x + 56 - 56 = 7 - 56 7x = -49Isolate x term: Finally, we divide both sides of the equation by 7 to solve for x. 7x / 7 = -49 / 7 x = -7

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Solve using substitution. $\newline$ $y = -7$ $\newline$ $7x - 8y = 7$ $\newline$ (_, _)

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Precalculus

Solve a system of equations using substitution

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Q. Solve using substitution.

\newline

y = -7

\newline

7x - 8y = 7

\newline

(_____, _____)

Given value of y: First, we are given the value of $y$ , which is $-7$ . We need to substitute this value into the second equation to find the value of $x$ . $y = -7$ $7x - 8y = 7$ Substitute $y = -7$ into the second equation: $7x - 8(-7) = 7$
Substitute $y$ into equation: Now, we simplify the equation by multiplying $-8$ with $-7$ and then solve for $x$ . $7x + 56 = 7$
Simplify and solve for $x$ : Next, we subtract $56$ from both sides of the equation to isolate the term with $x$ . $7x + 56 - 56 = 7 - 56$ $7x = -49$
Isolate x term: Finally, we divide both sides of the equation by $7$ to solve for $x$ . $\newline$ $\frac{7x}{7} = \frac{-49}{7}$ $\newline$ $x = -7$