Solve using substitution. y = –6 –10x − 10y = 10 (_____, _____)

Substitute y = –6: We are given y = –6 and need to substitute this value into the equation –10x − 10y = 10 to find the value of x. Substitute y = –6 into the equation: –10x − 10(–6) = 10Simplify the equation: Now, simplify the equation by multiplying 10 by –6: –10x + 60 = 10Isolate the variable x: Next, we need to isolate the variable x. To do this, we subtract 60 from both sides of the equation: –10x + 60 - 60 = 10 - 60 –10x = –50Divide to solve for x: Finally, we divide both sides of the equation by –10 to solve for x: –10x / –10 = –50 / –10 x = 5

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Solve using substitution. $\newline$ $y = -6$ $\newline$ $-10x - 10y = 10$ $\newline$ (_, _)

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Precalculus

Solve a system of equations using substitution

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Q. Solve using substitution.

\newline

y = -6

\newline

-10x - 10y = 10

\newline

(_____, _____)

Substitute $y = -6$ : We are given $y = -6$ and need to substitute this value into the equation $-10x - 10y = 10$ to find the value of $x$ . Substitute $y = -6$ into the equation: $-10x - 10(-6) = 10$
Simplify the equation: Now, simplify the equation by multiplying $10$ by $–6$ : $–10x + 60 = 10$
Isolate the variable $x$ : Next, we need to isolate the variable $x$ . To do this, we subtract $60$ from both sides of the equation: $\newline$ $-10x + 60 - 60 = 10 - 60$ $\newline$ $-10x = -50$
Divide to solve for x: Finally, we divide both sides of the equation by $–10$ to solve for $x$ : $\frac{–10x}{–10} = \frac{–50}{–10}$ $x = 5$