Solve using substitution. 8x + 6y = 14 y = 9 (_____, _____)

Substitute y = 9: Substitute y = 9 into the first equation. We are given 8x + 6y = 14 and y = 9. Substitute 9 for y in the first equation. 8x + 6(9) = 14 8x + 54 = 14Solve for x: Solve for x. Isolate the variable term by subtracting 54 from both sides of the equation. 8x + 54 - 54 = 14 - 54 8x = -40Divide by 8: Divide both sides by 8 to find the value of x. 8x / 8 = -40 / 8 x = -5Write as ordered pair: Write the solution as an ordered pair. We found x = -5 and we are given y = 9. The solution in the form of an ordered pair is (x, y). The solution is (-5, 9).

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Solve using substitution. $\newline$ $8x + 6y = 14$ $\newline$ $y = 9$ $\newline$ (_, _)

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Algebra 2

Solve a system of equations using substitution

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Q. Solve using substitution.

\newline

8x + 6y = 14

\newline

y = 9

\newline

(_____, _____)

Substitute $y = 9$ : Substitute $y = 9$ into the first equation. $\newline$ We are given $8x + 6y = 14$ and $y = 9$ . Substitute $9$ for $y$ in the first equation. $\newline$ $8x + 6(9) = 14$ $\newline$ $8x + 54 = 14$
Solve for x: Solve for x. $\newline$ Isolate the variable term by subtracting $54$ from both sides of the equation. $\newline$ $8x + 54 - 54 = 14 - 54$ $\newline$ $8x = -40$
Divide by $8$ : Divide both sides by $8$ to find the value of $x$ . $\frac{8x}{8} = \frac{-40}{8}$ $x = -5$
Write as ordered pair: Write the solution as an ordered pair. $\newline$ We found $x = -5$ and we are given $y = 9$ . The solution in the form of an ordered pair is $(x, y)$ . $\newline$ The solution is $(-5, 9)$ .