Solve using substitution. –6x − 8y = –6 y = 3 (_____, _____)

Substitute y = 3: Substitute y = 3 into the equation –6x − 8y = –6 and then simplify. This gives us –6x − 8(3) = –6.Simplify with substitution: Simplify the equation by multiplying 8 by 3. This gives us –6x − 24 = –6.Isolate x term: Add 24 to both sides of the equation to isolate the term with x. This gives us –6x = 18.Solve for x: Divide both sides of the equation by –6 to solve for x. This gives us x = –3.Write coordinate point: We found that x = –3 and y = 3. Write the solution as a coordinate point. The coordinate point is (–3, 3).

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Solve using substitution. $\newline$ $-6x - 8y = -6$ $\newline$ $y = 3$ $\newline$ (_, _)

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Algebra 2

Solve a system of equations using substitution

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Q. Solve using substitution.

\newline

-6x - 8y = -6

\newline

y = 3

\newline

(_____, _____)

Substitute $y = 3$ : Substitute $y = 3$ into the equation $–6x − 8y = –6$ and then simplify. This gives us $–6x − 8(3) = –6$ .
Simplify with substitution: Simplify the equation by multiplying $8$ by $3$ . This gives us $-6x - 24 = -6$ .
Isolate x term: Add $24$ to both sides of the equation to isolate the term with $x$ . This gives us $-6x = 18$ .
Solve for x: Divide both sides of the equation by $-6$ to solve for $x$ . This gives us $x = -3$ .
Write coordinate point: We found that $x = -3$ and $y = 3$ . Write the solution as a coordinate point. The coordinate point is $(-3, 3)$ .