Solve using substitution. –10x + 10y = –20 x = 4 (_____, _____)

Substitute x = 4: Substitute x = 4 into the equation –10x + 10y = –20. Calculation: –10(4) + 10y = –20, which simplifies to –40 + 10y = –20.Solve for y: Solve for y in the equation –40 + 10y = –20. Calculation: Add 40 to both sides to get 10y = 20.Divide to find y: Divide both sides by 10 to find the value of y. Calculation: y = 20 / 10, which simplifies to y = 2.Write solution as coordinate point: We found that x = 4 and y = 2. Write the solution as a coordinate point. The coordinate point is (4, 2).

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Solve using substitution. $\newline$ $-10x + 10y = -20$ $\newline$ $x = 4$ $\newline$ (_, _)

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Algebra 2

Solve a system of equations using substitution

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Q. Solve using substitution.

\newline

-10x + 10y = -20

\newline

x = 4

\newline

(_____, _____)

Substitute $x = 4$ : Substitute $x = 4$ into the equation $–10x + 10y = –20$ . $\newline$ Calculation: $–10(4) + 10y = –20$ , which simplifies to $–40 + 10y = –20$ .
Solve for y: Solve for y in the equation $-40 + 10y = -20$ . $\newline$ Calculation: Add $40$ to both sides to get $10y = 20$ .
Divide to find $y$ : Divide both sides by $10$ to find the value of $y$ . $\newline$ Calculation: $y = \frac{20}{10}$ , which simplifies to $y = 2$ .
Write solution as coordinate point: We found that $x = 4$ and $y = 2$ . Write the solution as a coordinate point. $\newline$ The coordinate point is $(4, 2)$ .