Solve using elimination. –7x + 4y = –9 –x + 4y = –15 (_____, _____)

Write Equations: Write down the system of equations to be solved using elimination. –7x + 4y = –9 –x + 4y = –15Multiply Second Equation: Multiply the second equation by 7 to make the coefficients of x in both equations equal in magnitude but opposite in sign. 7(–x + 4y) = 7(–15) This gives us: –7x + 28y = –105Add Equations: Add the new equation from Step 2 to the first equation to eliminate the x variable. (–7x + 4y) + (–7x + 28y) = (–9) + (–105) This simplifies to: –14x + 32y = –114

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Solve using elimination. $\newline$ $-7x + 4y = -9$ $\newline$ $-x + 4y = -15$ $\newline$ (_, _)

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Grade 8

Solve a system of equations using elimination

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Q. Solve using elimination.

\newline

-7x + 4y = -9

\newline

-x + 4y = -15

\newline

(_____, _____)

Write Equations: Write down the system of equations to be solved using elimination. $\newline$ $-7x + 4y = -9$ $\newline$ $-x + 4y = -15$
Multiply Second Equation: Multiply the second equation by $7$ to make the coefficients of $x$ in both equations equal in magnitude but opposite in sign. $\newline$ $7(-x + 4y) = 7(-15)$ $\newline$ This gives us: $\newline$ $-7x + 28y = -105$
Add Equations: Add the new equation from Step $2$ to the first equation to eliminate the $x$ variable. $\newline$ $(-7x + 4y) + (-7x + 28y) = (-9) + (-105)$ $\newline$ This simplifies to: $\newline$ $-14x + 32y = -114$