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Solve using elimination.\newline6x+4y=12-6x + 4y = 12\newline7x+4y=18-7x + 4y = 18\newline(_____, _____)

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Q. Solve using elimination.\newline6x+4y=12-6x + 4y = 12\newline7x+4y=18-7x + 4y = 18\newline(_____, _____)
  1. Set up equations: First, we need to set up the equations to eliminate one of the variables. We have the following system of equations:\newline6x+4y=12-6x + 4y = 12\newline7x+4y=18-7x + 4y = 18\newlineSince the coefficients of yy are the same, we can subtract one equation from the other to eliminate yy.
  2. Subtract equations: Subtract the first equation from the second equation:\newline(7x+4y)(6x+4y)=1812(-7x + 4y) - (-6x + 4y) = 18 - 12\newlineThis simplifies to:\newline7x+4y(6x)4y=1812-7x + 4y - (-6x) - 4y = 18 - 12
  3. Simplify equation: Simplify the equation by combining like terms: \newline7x+6x=1812-7x + 6x = 18 - 12\newlineThis results in:\newlinex=6-x = 6
  4. Find x value: To find the value of x, we divide both sides by 1–1:x1=61\frac{–x}{–1} = \frac{6}{–1}This gives us:x=6x = –6
  5. Substitute xx into equation: Now that we have the value of xx, we can substitute it into one of the original equations to find the value of yy. Let's use the first equation:\newline6x+4y=12-6x + 4y = 12\newlineSubstitute x=6x = -6 into the equation:\newline6(6)+4y=12-6(-6) + 4y = 12
  6. Perform multiplication: Perform the multiplication: 36+4y=1236 + 4y = 12
  7. Subtract to solve for y: Subtract 3636 from both sides to solve for yy: \newline4y=12364y = 12 - 36\newline4y=244y = -24
  8. Divide to find yy: Divide both sides by 44 to find the value of yy:
    y=244y = -\frac{24}{4}
    y=6y = -6

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