Q. Solve using elimination.6x+3y=−12−8x−3y=10(_____, _____)
Write Equations: Write down the system of equations to be solved using elimination.6x+3y=−12−8x−3y=10
Add Equations: Add the two equations together to eliminate the y variable.(6x+3y)+(–8x−3y)=–12+10
Find x: Perform the addition to find the value of x.6x−8x+3y−3y=−12+10−2x=−2
Solve for x: Solve for x by dividing both sides of the equation by -2").\(\newline\$-2x / -2 = -2 / -2\)\(\newline\)\(x = 1\)
Substitute \(x\): Substitute the value of \(x\) back into one of the original equations to solve for \(y\). We'll use the first equation.\[6(1) + 3y = -12\]\[6 + 3y = -12\]
Isolate y: Subtract \(6\) from both sides of the equation to isolate the term with \(y\).\(\newline\)\(3y = -12 - 6\)\(\newline\)\(3y = -18\)
Solve for y: Divide both sides of the equation by \(3\) to solve for y.\(\newline\)\(\frac{3y}{3} = \frac{-18}{3}\)\(\newline\)\(y = -6\)
More problems from Solve a system of equations using elimination