Solve using elimination. 6x + 10y = 16 9x + 10y = 4 (_____, _____)

Equations: System of equations: 6x + 10y = 16 9x + 10y = 4 Which variable should we eliminate? Both equations have the variable y with the same coefficient, so we will eliminate y.Eliminate Variable: System of equations: 6x + 10y = 16 9x + 10y = 4 Which operation should we use to eliminate y? Coefficients of y: 10 and 10 Here the coefficients are the same, we should subtract the second equation from the first.Subtract Equations: Subtract the second equation from the first to eliminate y. (6x + 10y) - (9x + 10y) = 16 - 4 6x + 10y - 9x - 10y = 12 -3x = 12Solve for x: Solve for x. Divide both sides of the equation by -3. (-3x) / -3 = 12 / -3 x = -4Substitute x: Substitute x = -4 into one of the original equations to solve for y. Let's use the first equation 6x + 10y = 16. 6(-4) + 10y = 16 -24 + 10y = 16Solve for y: Solve for y. Add 24 to both sides of the equation. -24 + 10y + 24 = 16 + 24 10y = 40 Divide both sides by 10. y = 4Final Solution: We found: x = -4 y = 4 Write the solution as a coordinate point. Solution: (-4, 4)

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Solve using elimination. $\newline$ $6x + 10y = 16$ $\newline$ $9x + 10y = 4$ $\newline$ (_, _)

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Grade 8

Solve a system of equations using elimination

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Q. Solve using elimination.

\newline

6x + 10y = 16

\newline

9x + 10y = 4

\newline

(_____, _____)

Equations: System of equations: $\newline$ $6x + 10y = 16$ $\newline$ $9x + 10y = 4$ $\newline$ Which variable should we eliminate? $\newline$ Both equations have the variable $y$ with the same coefficient, so we will eliminate $y$ .
Eliminate Variable: System of equations: $\newline$ $6x + 10y = 16$ $\newline$ $9x + 10y = 4$ $\newline$ Which operation should we use to eliminate $y$ ? $\newline$ Coefficients of $y$ : $10$ and $10$ $\newline$ Here the coefficients are the same, we should subtract the second equation from the first.
Subtract Equations: Subtract the second equation from the first to eliminate $y$ . $(6x + 10y) - (9x + 10y) = 16 - 4$ $6x + 10y - 9x - 10y = 12$ $-3x = 12$
Solve for x: Solve for x. $\newline$ Divide both sides of the equation by -3＂).$\newline\$(-3x) / -3 = 12 / -3$$\newline$$x = -4$
Substitute $x$: Substitute $x = -4$ into one of the original equations to solve for $y$. Let's use the first equation $6x + 10y = 16$.$\newline$$6(-4) + 10y = 16$$\newline$$-24 + 10y = 16$
Solve for y: Solve for y.$\newline$Add $24$ to both sides of the equation.$\newline$$-24 + 10y + 24 = 16 + 24$$\newline$$10y = 40$$\newline$Divide both sides by $10$.$\newline$$y = 4$
Final Solution: We found:$\newline$$x = -4$$\newline$$y = 4$$\newline$Write the solution as a coordinate point.$\newline$Solution: $(-4, 4)$