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Solve using elimination.\newline5x8y=35x - 8y = 3\newline5x+10y=155x + 10y = -15\newline(_____, _____)

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Q. Solve using elimination.\newline5x8y=35x - 8y = 3\newline5x+10y=155x + 10y = -15\newline(_____, _____)
  1. Set Up Equations: First, we need to set up the equations to eliminate one of the variables. We can do this by subtracting one equation from the other since the coefficients of xx are the same in both equations.5x8y=35x − 8y = 35x+10y=155x + 10y = −15Subtract the second equation from the first one to eliminate the xx variable.(5x8y)(5x+10y)=3(15)(5x − 8y) - (5x + 10y) = 3 - (−15)
  2. Subtract Equations: Now, perform the subtraction:\newline5x5x8y10y=3+155x - 5x - 8y - 10y = 3 + 15\newlineThis simplifies to:\newline0x18y=180x - 18y = 18\newlineSince 0x0x is 00, we can ignore it, and we are left with:\newline18y=18-18y = 18
  3. Perform Subtraction: Next, we solve for yy by dividing both sides of the equation by 18-18:18y18=1818\frac{-18y}{-18} = \frac{18}{-18}y=1y = -1
  4. Solve for y: Now that we have the value of yy, we can substitute it back into one of the original equations to solve for xx. We'll use the first equation:\newline5x8y=35x − 8y = 3\newline5x8(1)=35x − 8(-1) = 3\newline5x+8=35x + 8 = 3
  5. Substitute Back: Subtract 88 from both sides to solve for xx: \newline5x+88=385x + 8 - 8 = 3 - 8\newline5x=55x = -5
  6. Solve for x: Finally, divide both sides by 55 to find the value of x:\newline5x5=55\frac{5x}{5} = \frac{-5}{5}\newlinex=1x = -1

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