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Solve using elimination.\newline5x+3y=35x + 3y = -3\newline8x3y=6-8x - 3y = -6\newline(_____, _____)

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Q. Solve using elimination.\newline5x+3y=35x + 3y = -3\newline8x3y=6-8x - 3y = -6\newline(_____, _____)
  1. Write Equations: Write down the system of equations to be solved using elimination.\newline5x+3y=35x + 3y = -3\newline8x3y=6-8x - 3y = -6
  2. Add Equations: Add the two equations together to eliminate the yy variable.\newline(5x+3y)+(8x3y)=3+(6)(5x + 3y) + (–8x − 3y) = –3 + (–6)
  3. Find x: Perform the addition to find the value of x.\newline5x8x+3y3y=365x - 8x + 3y - 3y = -3 - 6\newline3x=9-3x = -9
  4. Solve for x: Solve for x by dividing both sides of the equation by -3").\(\newline\$-3x / -3 = -9 / -3\)\(\newline\)\(x = 3\)
  5. Substitute \(x\): Substitute the value of \(x\) back into one of the original equations to solve for \(y\). We'll use the first equation: \(5x + 3y = -3\).\(\newline\)\(5(3) + 3y = -3\)
  6. Simplify Equation: Perform the multiplication to simplify the equation. \(15 + 3y = -3\)
  7. Subtract \(15\): Subtract \(15\) from both sides of the equation to solve for \(y\).\[3y = -3 - 15\]\[3y = -18\]
  8. Divide for y: Divide both sides of the equation by \(3\) to find the value of y.\(\newline\)\(\frac{3y}{3} = \frac{-18}{3}\)\(\newline\)\(y = -6\)

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