Solve using elimination. –4x − 2y = 16 –6x + 2y = 4 (_____, _____)

Write Equations: Write down the system of equations. –4x − 2y = 16 –6x + 2y = 4Add Equations: Add the two equations together to eliminate the y variable. (–4x − 2y) + (–6x + 2y) = 16 + 4Find x: Perform the addition to find the value of x. –4x + (–6x) = –10x −2y + 2y = 0 (y terms cancel out) 16 + 4 = 20 So, we have –10x = 20Solve for x: Solve for x by dividing both sides of the equation by –10. –10x / –10 = 20 / –10 x = –2Substitute x: Substitute x = –2 into one of the original equations to find the value of y. We can use the first equation. –4(–2) − 2y = 16Solve for y: Perform the multiplication and solve for y. 8 − 2y = 16Isolate y: Subtract 8 from both sides of the equation to isolate the term with y. −2y = 16 − 8 −2y = 8Find y: Divide both sides of the equation by –2 to find the value of y. −2y / –2 = 8 / –2 y = –4

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Solve using elimination. $\newline$ $-4x - 2y = 16$ $\newline$ $-6x + 2y = 4$ $\newline$ (_, _)

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Grade 8

Solve a system of equations using elimination

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Q. Solve using elimination.

\newline

-4x - 2y = 16

\newline

-6x + 2y = 4

\newline

(_____, _____)

Write Equations: Write down the system of equations. $\newline$ $-4x - 2y = 16$ $\newline$ $-6x + 2y = 4$
Add Equations: Add the two equations together to eliminate the $y$ variable. $\newline$ $(-4x - 2y) + (-6x + 2y) = 16 + 4$
Find $x$ : Perform the addition to find the value of $x$ . $\newline$ $-4x + (-6x) = -10x$ $\newline$ $-2y + 2y = 0$ ( $y$ terms cancel out) $\newline$ $16 + 4 = 20$ $\newline$ So, we have $-10x = 20$
Solve for x: Solve for x by dividing both sides of the equation by $–10$ . $\frac{–10x}{–10} = \frac{20}{–10}$ $x = –2$
Substitute $x$ : Substitute $x = -2$ into one of the original equations to find the value of $y$ . We can use the first equation. $\,-4(-2) - 2y = 16$
Solve for y: Perform the multiplication and solve for y. $8 - 2y = 16$
Isolate y: Subtract $8$ from both sides of the equation to isolate the term with $y$ . $\newline$ $-2y = 16 - 8$ $\newline$ $-2y = 8$
Find $y$ : Divide both sides of the equation by $–2$ to find the value of $y$ . $\frac{–2y}{–2} = \frac{8}{–2}$ $y = –4$