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Let’s check out your problem:
Solve using elimination.
\newline
−
3
x
−
6
y
=
12
-3x - 6y = 12
−
3
x
−
6
y
=
12
\newline
3
x
+
7
y
=
−
18
3x + 7y = -18
3
x
+
7
y
=
−
18
\newline
(_____, _____)
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Math Problems
Grade 8
Solve a system of equations using elimination
Full solution
Q.
Solve using elimination.
\newline
−
3
x
−
6
y
=
12
-3x - 6y = 12
−
3
x
−
6
y
=
12
\newline
3
x
+
7
y
=
−
18
3x + 7y = -18
3
x
+
7
y
=
−
18
\newline
(_____, _____)
Write Equations:
Write down the
system of equations
to be solved using elimination.
\newline
−
3
x
−
6
y
=
12
-3x - 6y = 12
−
3
x
−
6
y
=
12
\newline
3
x
+
7
y
=
−
18
3x + 7y = -18
3
x
+
7
y
=
−
18
Add Equations:
Add the two equations together to eliminate the
x
x
x
variable.
\newline
(
−
3
x
−
6
y
)
+
(
3
x
+
7
y
)
=
12
+
(
−
18
)
(-3x - 6y) + (3x + 7y) = 12 + (-18)
(
−
3
x
−
6
y
)
+
(
3
x
+
7
y
)
=
12
+
(
−
18
)
Perform Addition:
Perform the addition to eliminate the
x
x
x
variable.
−
3
x
+
3
x
−
6
y
+
7
y
=
12
−
18
\,-3x + 3x - 6y + 7y = 12 - 18
−
3
x
+
3
x
−
6
y
+
7
y
=
12
−
18
0
x
+
1
y
=
−
6
\,0x + 1y = -6
0
x
+
1
y
=
−
6
This simplifies to
y
=
−
6
y = -6
y
=
−
6
.
Substitute and Solve (
y
y
y
):
Substitute
y
=
−
6
y = -6
y
=
−
6
into one of the original equations to solve for
x
x
x
. We'll use the first equation.
\newline
−
3
x
−
6
(
−
6
)
=
12
-3x - 6(-6) = 12
−
3
x
−
6
(
−
6
)
=
12
Perform Multiplication:
Perform the multiplication and solve for
x
x
x
.
−
3
x
+
36
=
12
\,-3x + 36 = 12
−
3
x
+
36
=
12
Isolate x:
Subtract
36
36
36
from both sides of the equation to isolate the term with
x
x
x
.
\newline
−
3
x
+
36
−
36
=
12
−
36
-3x + 36 - 36 = 12 - 36
−
3
x
+
36
−
36
=
12
−
36
\newline
−
3
x
=
−
24
-3x = -24
−
3
x
=
−
24
Divide and Solve
x
x
x
:
Divide both sides by
–
3
–3
–3
to solve for
x
x
x
.
–
3
x
–
3
=
–
24
–
3
\frac{–3x}{–3} = \frac{–24}{–3}
–3
–3
x
=
–3
–24
x
=
8
x = 8
x
=
8
Write Solution:
Write down the solution to the system of equations.
\newline
The solution is
(
x
,
y
)
=
(
8
,
−
6
)
(x, y) = (8, -6)
(
x
,
y
)
=
(
8
,
−
6
)
.
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Question
Solve using substitution.
5
x
−
2
y
=
−
7
5x - 2y = -7
5
x
−
2
y
=
−
7
x
=
−
5
x = -5
x
=
−
5
(_,_)
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Question
Is
(
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)
(1,1)
(
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\newline
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y
=
14
4x + 10y = 14
4
x
+
10
y
=
14
\newline
x
+
6
y
=
7
x + 6y = 7
x
+
6
y
=
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\newline
Choices:
\newline
(A) yes
\newline
(B) no
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Question
Which describes the system of equations below?
\newline
y
=
–
3
x
+
9
y = –3x + 9
y
=
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x
+
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\newline
y
=
–
3
x
+
9
y = –3x + 9
y
=
–3
x
+
9
\newline
Choices:
\newline
(A) consistent and independent
\text{(A) consistent and independent}
(A) consistent and independent
\newline
(B) consistent and dependent
\text{(B) consistent and dependent}
(B) consistent and dependent
\newline
(C) inconsistent
\text{(C) inconsistent}
(C) inconsistent
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Question
Solve using elimination.
\newline
7
x
−
8
y
=
−
17
7x - 8y = -17
7
x
−
8
y
=
−
17
\newline
−
7
x
+
3
y
=
2
-7x + 3y = 2
−
7
x
+
3
y
=
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\newline
(
_
_
_
_
,
_
_
_
_
)
(\_\_\_\_, \_\_\_\_)
(
____
,
____
)
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Question
Solve.
\newline
x
=
−
2
x = -2
x
=
−
2
\newline
−
2
x
+
2
y
=
−
8
-2x + 2y = -8
−
2
x
+
2
y
=
−
8
\newline
(
_
_
_
_
,
_
_
_
_
)
(\_\_\_\_, \_\_\_\_)
(
____
,
____
)
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Posted 8 months ago
Question
Write a system of equations to describe the situation below, solve using any method, and fill in the blanks.
\newline
At a community barbecue, Mrs. Wilkerson and Mr. Hogan are buying dinner for their families. Mrs. Wilkerson purchases
3
3
3
hot dog meals and
3
3
3
hamburger meals, paying a total of
$
36
\$36
$36
. Mr. Hogan buys
1
1
1
hot dog meal and
3
3
3
hamburger meals, spending
$
26
\$26
$26
in all. How much do the meals cost?
\newline
Hot dog meals cost
$
\$
$
_______ each, and hamburger meals cost
$
\$
$
________ each.
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Question
Solve the system of equations by substitution.
\newline
−
3
x
−
y
−
3
z
=
−
11
-3x - y - 3z = -11
−
3
x
−
y
−
3
z
=
−
11
\newline
z
=
5
z = 5
z
=
5
\newline
x
−
y
+
3
z
=
19
x - y + 3z = 19
x
−
y
+
3
z
=
19
\newline
(____.____,____)
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Posted 5 months ago
Question
Solve the system of equations by elimination.
\newline
x
−
3
y
−
2
z
=
10
x - 3y - 2z = 10
x
−
3
y
−
2
z
=
10
\newline
3
x
+
2
y
+
2
z
=
14
3x + 2y + 2z = 14
3
x
+
2
y
+
2
z
=
14
\newline
2
x
−
3
y
−
2
z
=
16
2x - 3y - 2z = 16
2
x
−
3
y
−
2
z
=
16
\newline
(
_
,
_
,
_
)
(\_,\_,\_)
(
_
,
_
,
_
)
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Question
Solve the system of equations.
\newline
y
=
x
2
+
36
x
+
3
y = x^2 + 36x + 3
y
=
x
2
+
36
x
+
3
\newline
y
=
22
x
−
37
y = 22x - 37
y
=
22
x
−
37
\newline
Write the coordinates in exact form. Simplify all fractions and radicals.
\newline
(
_
,
_
)
(\_,\_)
(
_
,
_
)
\newline
(
_
,
_
)
(\_,\_)
(
_
,
_
)
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Question
Solve the system of equations.
\newline
y
=
−
x
−
24
y = -x - 24
y
=
−
x
−
24
\newline
x
2
+
y
2
=
488
x^2 + y^2 = 488
x
2
+
y
2
=
488
\newline
Write the coordinates in exact form. Simplify all fractions and radicals.
\newline
(
_
,
_
)
(\_,\_)
(
_
,
_
)
\newline
(
_
,
_
)
(\_,\_)
(
_
,
_
)
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Posted 5 months ago
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