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Let’s check out your problem:
Solve using elimination.
\newline
3
x
+
6
y
=
−
12
3x + 6y = -12
3
x
+
6
y
=
−
12
\newline
−
3
x
−
4
y
=
−
2
-3x - 4y = -2
−
3
x
−
4
y
=
−
2
\newline
(_____, _____)
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Math Problems
Precalculus
Solve a system of equations using elimination
Full solution
Q.
Solve using elimination.
\newline
3
x
+
6
y
=
−
12
3x + 6y = -12
3
x
+
6
y
=
−
12
\newline
−
3
x
−
4
y
=
−
2
-3x - 4y = -2
−
3
x
−
4
y
=
−
2
\newline
(_____, _____)
Write Equations:
Write down the
system of equations
to be solved using elimination.
\newline
3
x
+
6
y
=
−
12
3x + 6y = -12
3
x
+
6
y
=
−
12
\newline
−
3
x
−
4
y
=
−
2
-3x - 4y = -2
−
3
x
−
4
y
=
−
2
Add Equations:
Add the two equations together to eliminate the
x
x
x
variable.
\newline
(
3
x
+
6
y
)
+
(
–
3
x
−
4
y
)
=
–
12
+
(
–
2
)
(3x + 6y) + (–3x − 4y) = –12 + (–2)
(
3
x
+
6
y
)
+
(
–3
x
−4
y
)
=
–12
+
(
–2
)
Find
y
y
y
:
Perform the addition to find the value of
y
y
y
.
3
x
−
3
x
+
6
y
−
4
y
=
−
12
−
2
3x - 3x + 6y - 4y = -12 - 2
3
x
−
3
x
+
6
y
−
4
y
=
−
12
−
2
0
x
+
2
y
=
−
14
0x + 2y = -14
0
x
+
2
y
=
−
14
2
y
=
−
14
2y = -14
2
y
=
−
14
Solve for y:
Divide both sides of the equation by
2
2
2
to solve for y.
\newline
2
y
÷
2
=
−
14
÷
2
2y \div 2 = -14 \div 2
2
y
÷
2
=
−
14
÷
2
\newline
y
=
−
7
y = -7
y
=
−
7
Substitute for x:
Substitute the value of
y
y
y
back into one of the original equations to solve for
x
x
x
. We can use the first equation.
3
x
+
6
(
−
7
)
=
−
12
3x + 6(-7) = -12
3
x
+
6
(
−
7
)
=
−
12
Solve for x:
Perform the multiplication and solve for x.
\newline
3
x
−
42
=
−
12
3x - 42 = -12
3
x
−
42
=
−
12
\newline
3
x
=
−
12
+
42
3x = -12 + 42
3
x
=
−
12
+
42
\newline
3
x
=
30
3x = 30
3
x
=
30
Final Solution:
Divide both sides of the equation by
3
3
3
to find the value of x.
\newline
3
x
÷
3
=
30
÷
3
3x \div 3 = 30 \div 3
3
x
÷
3
=
30
÷
3
\newline
x
=
10
x = 10
x
=
10
More problems from Solve a system of equations using elimination
Question
Solve using substitution.
5
x
−
2
y
=
−
7
5x - 2y = -7
5
x
−
2
y
=
−
7
x
=
−
5
x = -5
x
=
−
5
(_,_)
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Posted 5 months ago
Question
Is
(
1
,
1
)
(1,1)
(
1
,
1
)
a solution to this system of equations?
\newline
4
x
+
10
y
=
14
4x + 10y = 14
4
x
+
10
y
=
14
\newline
x
+
6
y
=
7
x + 6y = 7
x
+
6
y
=
7
\newline
Choices:
\newline
(A) yes
\newline
(B) no
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Posted 5 months ago
Question
Which describes the system of equations below?
\newline
y
=
–
3
x
+
9
y = –3x + 9
y
=
–3
x
+
9
\newline
y
=
–
3
x
+
9
y = –3x + 9
y
=
–3
x
+
9
\newline
Choices:
\newline
(A) consistent and independent
\text{(A) consistent and independent}
(A) consistent and independent
\newline
(B) consistent and dependent
\text{(B) consistent and dependent}
(B) consistent and dependent
\newline
(C) inconsistent
\text{(C) inconsistent}
(C) inconsistent
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Posted 5 months ago
Question
Solve using elimination.
\newline
7
x
−
8
y
=
−
17
7x - 8y = -17
7
x
−
8
y
=
−
17
\newline
−
7
x
+
3
y
=
2
-7x + 3y = 2
−
7
x
+
3
y
=
2
\newline
(
_
_
_
_
,
_
_
_
_
)
(\_\_\_\_, \_\_\_\_)
(
____
,
____
)
Get tutor help
Posted 5 months ago
Question
Solve.
\newline
x
=
−
2
x = -2
x
=
−
2
\newline
−
2
x
+
2
y
=
−
8
-2x + 2y = -8
−
2
x
+
2
y
=
−
8
\newline
(
_
_
_
_
,
_
_
_
_
)
(\_\_\_\_, \_\_\_\_)
(
____
,
____
)
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Posted 9 months ago
Question
Write a system of equations to describe the situation below, solve using any method, and fill in the blanks.
\newline
At a community barbecue, Mrs. Wilkerson and Mr. Hogan are buying dinner for their families. Mrs. Wilkerson purchases
3
3
3
hot dog meals and
3
3
3
hamburger meals, paying a total of
$
36
\$36
$36
. Mr. Hogan buys
1
1
1
hot dog meal and
3
3
3
hamburger meals, spending
$
26
\$26
$26
in all. How much do the meals cost?
\newline
Hot dog meals cost
$
\$
$
_______ each, and hamburger meals cost
$
\$
$
________ each.
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Posted 9 months ago
Question
Solve the system of equations by substitution.
\newline
−
3
x
−
y
−
3
z
=
−
11
-3x - y - 3z = -11
−
3
x
−
y
−
3
z
=
−
11
\newline
z
=
5
z = 5
z
=
5
\newline
x
−
y
+
3
z
=
19
x - y + 3z = 19
x
−
y
+
3
z
=
19
\newline
(____.____,____)
Get tutor help
Posted 5 months ago
Question
Solve the system of equations by elimination.
\newline
x
−
3
y
−
2
z
=
10
x - 3y - 2z = 10
x
−
3
y
−
2
z
=
10
\newline
3
x
+
2
y
+
2
z
=
14
3x + 2y + 2z = 14
3
x
+
2
y
+
2
z
=
14
\newline
2
x
−
3
y
−
2
z
=
16
2x - 3y - 2z = 16
2
x
−
3
y
−
2
z
=
16
\newline
(
_
,
_
,
_
)
(\_,\_,\_)
(
_
,
_
,
_
)
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Posted 5 months ago
Question
Solve the system of equations.
\newline
y
=
x
2
+
36
x
+
3
y = x^2 + 36x + 3
y
=
x
2
+
36
x
+
3
\newline
y
=
22
x
−
37
y = 22x - 37
y
=
22
x
−
37
\newline
Write the coordinates in exact form. Simplify all fractions and radicals.
\newline
(
_
,
_
)
(\_,\_)
(
_
,
_
)
\newline
(
_
,
_
)
(\_,\_)
(
_
,
_
)
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Posted 5 months ago
Question
Solve the system of equations.
\newline
y
=
−
x
−
24
y = -x - 24
y
=
−
x
−
24
\newline
x
2
+
y
2
=
488
x^2 + y^2 = 488
x
2
+
y
2
=
488
\newline
Write the coordinates in exact form. Simplify all fractions and radicals.
\newline
(
_
,
_
)
(\_,\_)
(
_
,
_
)
\newline
(
_
,
_
)
(\_,\_)
(
_
,
_
)
Get tutor help
Posted 5 months ago
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