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Solve using elimination.\newline3x3y=63x - 3y = -6\newline5x3y=205x - 3y = -20\newline(_____, _____)

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Q. Solve using elimination.\newline3x3y=63x - 3y = -6\newline5x3y=205x - 3y = -20\newline(_____, _____)
  1. Set up equations: First, we need to set up the equations to eliminate one of the variables. We have the following system of equations:\newline3x3y=63x − 3y = −6\newline5x3y=205x − 3y = −20\newlineWe can see that the coefficients of yy are the same but with opposite signs, so we can eliminate the yy variable by subtracting the first equation from the second.
  2. Subtract equations: Perform the subtraction of the two equations:\newline(5x3y)(3x3y)=(20)(6)(5x − 3y) − (3x − 3y) = (−20) − (−6)\newlineThis simplifies to:\newline5x3y3x+3y=20+65x − 3y − 3x + 3y = −20 + 6
  3. Simplify equation: Simplify the equation by combining like terms: 5x3x=20+65x - 3x = -20 + 6 2x=142x = -14
  4. Solve for x: Now, solve for x by dividing both sides of the equation by 22:\newline2x÷2=14÷22x \div 2 = -14 \div 2\newlinex=7x = -7
  5. Substitute x value: With the value of x found, we can substitute x=7x = -7 into one of the original equations to find the value of y. Let's use the first equation:\newline3x3y=63x - 3y = -6\newline3(7)3y=63(-7) - 3y = -6
  6. Simplify equation: Perform the multiplication and simplify the equation: 213y=6-21 - 3y = -6
  7. Isolate y term: Add 2121 to both sides of the equation to isolate the term with yy: \newline21+213y=6+21-21 + 21 - 3y = -6 + 21\newline3y=15-3y = 15
  8. Solve for y: Now, solve for y by dividing both sides of the equation by 3-3:3y÷(3)=15÷(3)−3y \div (−3) = 15 \div (−3)y=5y = –5

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